Current–Metric Locking and the Topological-Current Non-Protection Lemma

Current–Metric Locking and the Topological-Current Non-Protection Lemma

A record of the derivation: the sharpened condition for structural g = 2, the explicit failure of the metric-independent topological current, the profile-preserving deformation that closes the route, and the boundary of what remains open.

How to Read This Document

This is a record of a sustained derivation. It begins from a single structural condition — the relation Mκ = Λ implied by g = 2 — and ends with a clean negative result about the topological-current route and a sharp statement of the remaining open problem. The document labels every claim: proved, derived, conditional, ruled out, or open.

Labels used throughout.
LabelMeaning
ProvedFully established by an explicit construction or a closed argument.
DerivedFollows from a calculation under stated assumptions.
ConditionalHolds only under assumptions that have not been verified in general.
Ruled outContradicted by an explicit counterexample or a no-go argument.
OpenNo calculation has settled it.
CorrectedAn earlier claim in the derivation that was found to be wrong.

Part I — The Sharpened Condition

From Mκ = Λ to Current–Metric Locking

The starting point is structural g = 2 for a charged rotating soliton. In collective-coordinate language, the magnetic moment κ and the moment of inertia Λ satisfy

M κ = Λ

The structural g = 2 condition.

This is equivalent to a mixed-response statement. Writing the energy as

E(B, Ω) = M + ½ Λ Ω² − q κ Ω·B + ⋯

the condition becomes

∂²E/∂Ω_i∂B_j |₀ = −(q/M) ∂²E/∂Ω_i∂Ω_j |₀

This is a statement about the source-dependent soliton energy. It is not yet a statement about the microscopic theory. The sharpening is to ask what this requires of the moduli-space geometry.

Derived Rotation acts through rotational Killing vectors K_i^a on the moduli space. ↓ Derived Electromagnetism acts through a U(1) connection on moduli space, whose magnetic response one-form is Θ_EM^i. ↓ Derived The moment of inertia is Λ_ij = g_ab K_i^a K_j^b. ↓ Conditional Structural g = 2 is equivalent to Θ_EM^i(K_j) = (q/M) g(K_i, K_j). ↓ Conjectured The stronger geometric condition is Θ_EM^i = (q/M) K_i^♭ on the rotational subbundle.
The sharpened condition

Structural g = 2 requires current–metric locking: the electromagnetic magnetic-response one-form must equal the metric dual of the rotational Killing vector, up to q/M.

Θ_EM^i = (q/M) K_i^♭

This is much stronger than Mκ = Λ alone. It identifies a specific one-form on moduli space and demands that it be fixed by the rotational Killing vector. Nothing about topology, Bogomolny saturation, or Kähler geometry alone forces this identification.

Part II — The Topological-Current Route

The Metric-Independent Topological Current

The most natural candidate for a bosonic mechanism is a soliton whose electromagnetic current is a conserved topological current:

J_EM^μ = q_t B^μ, ∂_μ B^μ = 0

B^μ is the degree current of the SU(2) hedgehog.

If this is the whole story, then the electromagnetic response one-form Θ_EM is determined entirely by B^μ, independently of the kinetic sector of the theory. The question is whether topology can protect the locking condition.

The naive hope. Topology quantizes the charge q_t. Perhaps it also fixes the first spatial moment of the topological current, and therefore the magnetic moment, in terms of angular momentum. If so, g = 2 would follow kinematically.

The Off-Shell Test

For the SU(2) hedgehog with unit winding, the topological density B⁰(r) satisfies

4π ∫₀^∞ r² B⁰(r) dr = 1

Topology fixes the normalization.

But the magnetic first moment involves an extra factor of r²:

μ_top = (q_t/3) ⟨r²⟩_B Ω

⟨r²⟩_B = ∫ r² B⁰(r) d³x

Topology does not fix the first moment

The normalization integral ∫ B⁰ d³x is topological. The first moment ∫ r² B⁰ d³x is not. It depends on the profile of B⁰(r), and therefore on the soliton shape.

This is the first indication that the topological-current route cannot work by topology alone.

Part III — The Measure Mismatch in BPS Skyrme

BPS Skyrme

The BPS Skyrme model is the most favorable bosonic soliton to test: it has a first-order Bogomolny equation and a Bogomolny bound. Its Lagrangian is

ℒ_BPS = −λ²π⁴ B_μ B^μ − μ² V(U)

Squared baryon current plus a potential.

On a BPS solution the two terms are pointwise equal, so the static mass is

M = 2 λ² π⁴ ∫ ρ_B² d³x

The rotational inertia is obtained by rigidly rotating the density:

Λ = (4/3) λ² π⁴ ∫ r² ρ_B² d³x

Meanwhile the topological magnetic moment is

𝒦 = (q_t/3) ∫ r² ρ_B d³x

The Missing-Half Condition

The proposed identity for the topological contribution is

𝒦 = (q/2) (Λ/M)

Substituting the BPS expressions gives

q_t ⟨r²⟩_{ρ_B} = q ⟨r²⟩_{ρ_B²}

Two different moments of the profile.

The measure mismatch

The left side is the mean-square radius weighted by baryon density. The right side is the mean-square radius weighted by squared baryon density. These are different functionals of the profile.

Even for the maximally favorable case of a uniform density inside a ball, the two moments are equal, not in the ratio required by the missing-half condition. And the BPS equation does not enforce the ratio for a generic potential.

BPS saturation is not enough

Bogomolny saturation of the BPS Skyrme model does not, by itself, enforce the topological missing-half condition. The potential remains a deformation direction inside the BPS class, and it changes the two moments differently.

Part IV — Failed Deformation Candidates

The Strategy

The route forward is to construct an explicit profile-preserving deformation: a local, Lorentz-invariant, symmetry-preserving operator that

𝒪_*[φ₀] = 0, δ_static 𝒪_*[φ₀] = 0, δ²_Ω 𝒪_* ≠ 0

Such an operator leaves the static soliton and its mass unchanged to first order, while changing the rotational kinetic metric. If it does not couple to A_μ, it also leaves the topological current unchanged. Then D𝒞 ≠ 0, and the topological-current route is closed.

First-Derivative No-Go

The first candidate class is algebraic functions of the Gram tensor

X_{μν} = −½ Tr(L_μ L_ν)

For a static configuration, X_{00} = 0 and X_{0i} = 0. Under a rotation, X_{0i} = O(Ω), but the linear variation of any trace invariant vanishes because X^(0) has no temporal row or column.

First-derivative no-go

No smooth Lorentz scalar constructed algebraically only from X_{μν} can satisfy F[U₀] = 0 and δ_rot F ≠ 0 for a static SU(2) configuration.

Failed Higher-Derivative Candidates

CandidateReason it fails
W = ε^{μνρσ} Tr(L_μ L_ν L_ρ L_σ)Vanishes identically for SU(2): four one-forms in a three-dimensional Lie algebra.
(B^μ ∂_μ B²)²On the spherical rotor, B^i ∂_i B² = 0 because the rotation is tangential to level surfaces of B².
B^μ B^ν Tr(∂_μ L_ν)Identically zero: Tr(L_ν) = 0.
(Tr(L_μ L_ν) ∂^μ B^ν)²Vanishes at O(Ω²) on the hedgehog by symmetry of X_ij and antisymmetry of ∂_i v_j.
The recurring obstruction

All these failures share a common geometric origin. For a spherical hedgehog, the rotation velocity v = Ω × x is tangential, and every invariant radial vector is proportional to n. The contraction v·n vanishes. Meanwhile the only invariant rank-two spatial tensor is symmetric, so it cannot contract with the antisymmetric rotation gradient.

Part V — The Profile-Preserving Deformation

The Surviving Operator

The obstruction is broken by using the derivative of the topological current, not the current itself. Define

𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α)

L_α = U^{-1} ∂_α U.

This operator is local, Lorentz invariant, and symmetry preserving. It does not couple to A_μ.

Static Properties

Proved For any static configuration, B^μ = (B⁰, 0, 0, 0) and ∂₀L_α = 0. Therefore 𝒪_B[φ_static] = 0. ↓ Proved Since 𝒪_B is quadratic in B^μ ∂_μ L_α, its first variation on a static configuration also vanishes. ↓ Proved The static mass and static equations of motion are unchanged to first order.

The Rotor Matrix Element

Under a rigid rotation, the convective derivative 𝒟 = ∂_t + v·∇ annihilates the field itself, but it rotates the spatial covector index of L_i:

𝒟 L_i = −(∂_i v^j) L_j = −ω_i^j L_j

This surviving term gives the quadratic rotor matrix element. After angular integration,

∫ d³x 𝒪_B^(2) = (16π/3) Ω² ∫₀^∞ dr r² ρ(r)² (f’² + 2 sin²f / r²)

Nonzero rotor matrix element

The quadratic rotor matrix element is strictly positive for a nontrivial B = 1 hedgehog. The operator changes the rotational kinetic metric.

No Electromagnetic Response

Because 𝒪_B does not couple to A_μ, and because the topological current J_EM^μ = q_t B^μ is unchanged at linear order, the electromagnetic magnetic-response one-form Θ_EM is unchanged:

δ Θ_EM = 0, δ K^♭ ≠ 0

Therefore, if 𝒪_B is nonredundant, D𝒞 ≠ 0 and the topological-current route is closed.

Part VI — The Non-Redundancy Test

The Redundancy Question

An operator can fail to change the physics if it is a total derivative, proportional to the equations of motion, or removable by a field redefinition. The question is whether

𝒪_B = E_A Y^A + ∂_μ V^μ

for some local Y^A, V^μ.

The On-Shell Test

Evaluate on the true adiabatic rotating solution

φ_Ω = φ₀ + Ω Z_rot + Ω² η₂ + ⋯

Because 𝒪_B[φ₀] = 0 and D𝒪_B[φ₀] = 0, the quadratic matrix element is determined entirely by the rotational zero mode. The centrifugal correction η₂ does not contribute.

Suppose for contradiction that 𝒪_B = E_A Y^A + ∂_μ V^μ. On-shell, E_A = 0, so

𝒪_B = ∂_μ V^μ

Integrating over a closed rotational period T:

∫₀^T dt ∫ d³x ∂_μ V^μ = [∫ d³x V⁰]₀^T + ∫₀^T dt ∮_∞ dS_i V^i

The spatial boundary term vanishes by localization. The temporal term vanishes for a single-valued local V⁰ over a closed orbit. Therefore redundancy would imply

∫₀^T dt ∫ d³x 𝒪_B = 0

But the explicit matrix element gives TC Ω² + O(Ω³), which is nonzero for sufficiently small nonzero Ω.

Nonredundancy proved

Contradiction. Therefore 𝒪_B is not in the ideal generated by the equations of motion and total derivatives.

𝒪_B ∉ ⟨E_A⟩ + dΩ³_loc

Part VII — The Result and Its Boundary

The Lemma

Metric-independent topological-current non-protection lemma

For an SU(2) hedgehog whose electromagnetic coupling is supplied by a metric-independent topological current B^μ, current–metric locking cannot be protected solely by topology against arbitrary local Lorentz- and symmetry-preserving EFT deformations.

The proof is constructive. The operator 𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α) is local, symmetry-preserving, vanishes on every static configuration, has vanishing first static variation, has a strictly positive quadratic rotor matrix element, and is nonredundant by the closed-orbit on-shell argument.

The Stated Assumptions

AssumptionRole
U is neutral under the electromagnetic U(1)Ensures the deformation does not induce an explicit A_μ dependence.
J_EM^μ = q_t B^μDefines the metric-independent current.
Adiabatic on-shell expansion is validJustifies evaluating on the slowly rotating solution.
Standard locality and falloffEnsures the boundary terms vanish.

The Boundary

If U is charged under the electromagnetic U(1), the deformation may acquire explicit A_μ dependence through covariant derivatives. Then δΘ_EM need not vanish, and the argument does not directly apply. This is the common-generating-structure class.

The boundary is sharp. The metric-independent topological-current route is closed. The only surviving possibility is that J_EM and g_moduli descend from a common microscopic structure, so that any deformation changing the metric also changes the current in exactly the same way.

Addendum I — The Odd-Ω Lemma

Why F² Constructions Fail

Every attempt to construct a profile-preserving deformation as 𝒪_* = F² with F[U₀] = 0 and F[U_Ω] = O(Ω) fails for a structural reason.

Odd-Ω lemma for the action

For a spherically symmetric hedgehog, the integrated action has no term linear in Ω. The energy is even in Ω, and the first nontrivial term is the quadratic moment of inertia.

The proof is simple. The only invariant vector available is r̂. Any term linear in Ω must be of the form Ω·r̂ f(r), and the angular integral vanishes. Therefore F[U_Ω] starts at O(Ω²), and F² starts at O(Ω⁴) — too high order to affect the quadratic kinetic metric.

Correction to the F² strategy

Searching for F = O(Ω) is the wrong strategy. The correct target is a direct O(Ω²) operator satisfying 𝒪_*[U₀] = 0, δ_static 𝒪_*[U₀] = 0, and 𝒪_*[U_Ω] = c(r) Ω² + O(Ω⁴).

Addendum II — The Local Response Identity

The Next Theorem

The remaining question is independent of the topological-current construction. Define

𝒞_a^i = Θ_a^i − (q/M) g_ab K_i^b

Structural Dirac locking requires 𝒞 = 0 and D𝒞[𝒪] = 0 for every admissible symmetry-preserving local deformation 𝒪.

Next theorem. Classify the local identities capable of enforcing Θ_EM^i = (q/M) K_i^♭ under all allowed deformations.

Two Levels

LevelQuestion
Finite derivative orderChoose a basis of independent gauge-invariant local operators modulo IBP, EOM, and field redefinitions. Compute the tangent vectors δ_A𝒞. If they span a nonzero subspace, ordinary symmetry does not protect the locking.
All ordersDoes the local response kernel identity hold in the local-functional quotient?

The Local Response Identity

The all-orders question is whether

ℛ_Θ − (q/M) ℛ_g = E_A Y^A + ∂_μ X^μ + (gauge/Ward identities)

holds in the local-functional quotient. This is where a genuine protecting mechanism would have to live.

Criterion for candidate mechanisms

A BPS equation, special moduli-space geometry, SUSY algebra, anomaly/WZ structure, or hidden symmetry is relevant only if it can be traced all the way to this response identity. Merely constraining M, quantizing q, producing spin 1/2, or giving a beautiful moduli-space metric is insufficient.

Closing State

The topological-current branch is closed. The metric-independent-current non-protection lemma is proved under the stated assumptions. The profile-preserving operator is explicit, local, symmetry-preserving, nonredundant, and has a strictly positive rotor matrix element. It changes the rotational kinetic metric while leaving the topological electromagnetic current unchanged.

The only surviving possibility for structural g = 2 in a purely bosonic theory is that the electromagnetic current and the moduli-space metric descend from a common microscopic structure, so that any deformation changing the metric also changes the current in exactly the same way. SUSY is one known example, but whether a specific supersymmetric soliton enforces the electromagnetic relation is a separate theorem. Ordinary BPS saturation already failed this test.

The next theorem

Classify the local identities capable of enforcing Θ_EM^i = (q/M) K_i^♭ under all allowed deformations.

What Remains Open

  1. The local response identity. The condition ℛ_Θ = (q/M) ℛ_g modulo EOM, total derivatives, and gauge identities has not been classified.
  2. The charged case. If U is charged under the electromagnetic U(1), the deformation may acquire explicit A_μ dependence. The non-protection lemma does not directly apply.
  3. SUSY as a solution. Whether a specific supersymmetric soliton satisfies the electromagnetic relation is not established. A central charge or BPS mass relation does not automatically prove the magnetic-response identity.
  4. Purely bosonic common structures. Whether any purely bosonic local structure can enforce the locking condition for all admissible deformations is open.
  5. The finite-order rank problem. At each derivative order, the tangent vectors δ_A𝒞 have not been computed for a general basis of operators.

The Honest Summary

The derivation produced one clean negative result and one sharp open problem. The negative result: a metric-independent topological electromagnetic current cannot, by topology alone, protect current–metric locking. The proof is constructive and survives the on-shell redundancy test. The open problem: classify the local identities capable of enforcing the locking condition, or prove that no purely bosonic structure of this type exists for a charged π₃ soliton.

The problem is no longer “find a clever soliton profile that gives g = 2.” It is: does there exist a microscopic identity whose local response content forces the electromagnetic magnetic-response functional and the rotational kinetic functional to be the same functional up to q/M?

Record of a derivation. Proved results labeled as proved. Conditional results labeled as conditional. Ruled-out candidates listed with their obstructions. Corrections recorded alongside the claims they correct. Open problems listed.

Current–Metric Locking: The Topological-Current Route and the Charged-Case Boundary

Current–Metric Locking: The Topological-Current Route and the Charged-Case Boundary

A record of the derivation from structural g = 2 to the metric-independent topological-current non-protection lemma, and the precise boundary where the charged case remains open.

How to Read This Document

This is a record of a sustained derivation. It begins from the structural condition Mκ = Λ implied by g = 2 and follows the topology route as far as it goes. The neutral case is closed. The charged case is open, with a precise calculation pipeline. Every claim is labeled: proved, derived, conditional, ruled out, or open.

Labels used throughout.
LabelMeaning
ProvedFully established by an explicit construction or a closed argument.
DerivedFollows from a calculation under stated assumptions.
ConditionalHolds only under assumptions not yet verified in general.
Ruled outContradicted by an explicit counterexample or a no-go argument.
OpenNo calculation has settled it.
CorrectedAn earlier claim in the derivation that was found to be wrong.

Part I — The Sharpened Condition

From Mκ = Λ to Current–Metric Locking

The starting point is structural g = 2 for a charged rotating soliton. In collective-coordinate language, the magnetic moment κ and the moment of inertia Λ satisfy

M κ = Λ

The structural g = 2 condition.

This is equivalent to a mixed-response statement. Writing the energy as

E(B, Ω) = M + ½ Λ Ω² − q κ Ω·B + ⋯

the condition becomes

∂²E/∂Ω_i∂B_j |₀ = −(q/M) ∂²E/∂Ω_i∂Ω_j |₀

The sharpening is to ask what this requires of the moduli-space geometry. Rotation acts through rotational Killing vectors K_i^a. Electromagnetism acts through a U(1) connection whose magnetic response one-form is Θ_EM^i. The moment of inertia is Λ_ij = g_ab K_i^a K_j^b.

Derived Structural g = 2 is equivalent to Θ_EM^i(K_j) = (q/M) g(K_i, K_j). ↓ Conjectured The stronger geometric condition is Θ_EM^i = (q/M) K_i^♭ on the rotational subbundle. ↓ The target Structural g = 2 requires current–metric locking: the electromagnetic magnetic-response one-form must equal the metric dual of the rotational Killing vector, up to q/M.
The sharpened condition

Θ_EM^i = (q/M) K_i^♭

This is much stronger than Mκ = Λ alone. It identifies a specific one-form on moduli space and demands that it be fixed by the rotational Killing vector. Nothing about topology, Bogomolny saturation, or Kähler geometry alone forces this identification.

Part II — The Neutral Topological-Current Route

The Metric-Independent Topological Current

The most natural candidate for a bosonic mechanism is a soliton whose electromagnetic current is a conserved topological current:

J_EM^μ = q_t B^μ, ∂_μ B^μ = 0

B^μ is the degree current of the SU(2) hedgehog.

If this is the whole story, then Θ_EM is determined entirely by B^μ, independently of the kinetic sector. The question is whether topology can protect the locking condition.

The Off-Shell Test

For the SU(2) hedgehog with unit winding, the topological density B⁰(r) satisfies

4π ∫₀^∞ r² B⁰(r) dr = 1

Topology fixes the normalization.

But the magnetic first moment involves an extra factor of r²:

μ_top = (q_t/3) ⟨r²⟩_B Ω

⟨r²⟩_B = ∫ r² B⁰(r) d³x

Topology does not fix the first moment

The normalization integral ∫ B⁰ d³x is topological. The first moment ∫ r² B⁰ d³x is not. It depends on the profile of B⁰(r), and therefore on the soliton shape.

Part III — The Measure Mismatch in BPS Skyrme

BPS Skyrme

The BPS Skyrme model is the most favorable bosonic soliton to test. Its Lagrangian is

ℒ_BPS = −λ²π⁴ B_μ B^μ − μ² V(U)

Squared baryon current plus a potential.

On a BPS solution the two terms are pointwise equal, so the static mass is

M = 2 λ² π⁴ ∫ ρ_B² d³x

The rotational inertia is

Λ = (4/3) λ² π⁴ ∫ r² ρ_B² d³x

The topological magnetic moment is

𝒦 = (q_t/3) ∫ r² ρ_B d³x

The Missing-Half Condition

The proposed identity for the topological contribution is 𝒦 = (q/2)(Λ/M). Substituting the BPS expressions gives

q_t ⟨r²⟩_{ρ_B} = q ⟨r²⟩_{ρ_B²}

Two different moments of the profile.

The measure mismatch

The left side is the mean-square radius weighted by baryon density. The right side is the mean-square radius weighted by squared baryon density. These are different functionals of the profile.

BPS saturation is not enough

Bogomolny saturation of the BPS Skyrme model does not, by itself, enforce the topological missing-half condition. The potential remains a deformation direction inside the BPS class, and it changes the two moments differently.

Part IV — Failed Deformation Candidates

The Strategy

We need a profile-preserving deformation: a local, Lorentz-invariant, symmetry-preserving operator that

𝒪_*[φ₀] = 0, δ_static 𝒪_*[φ₀] = 0, δ²_Ω 𝒪_* ≠ 0

Such an operator leaves the static soliton and its mass unchanged, while changing the rotational kinetic metric. If it does not couple to A_μ, it also leaves the topological current unchanged.

Failed Candidates

CandidateReason it fails
F(X) with X_{μν} = −½ Tr(L_μ L_ν)No smooth algebraic scalar can satisfy F[U₀] = 0 and δ_rot F ≠ 0.
W = ε^{μνρσ} Tr(L_μ L_ν L_ρ L_σ)Vanishes identically for SU(2).
(B^μ ∂_μ B²)²On the spherical rotor, B^i ∂_i B² = 0.
B^μ B^ν Tr(∂_μ L_ν)Identically zero: Tr(L_ν) = 0.
(Tr(L_μ L_ν) ∂^μ B^ν)²Vanishes at O(Ω²) on the hedgehog by symmetry.

Part V — The Profile-Preserving Deformation

The Surviving Operator

The obstruction is broken by using the derivative of the topological current:

𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α)

L_α = U^{-1} ∂_α U.

This operator is local, Lorentz invariant, and symmetry preserving. It does not couple to A_μ.

Properties

Proved For any static configuration, B^μ = (B⁰, 0, 0, 0) and ∂₀L_α = 0. Therefore 𝒪_B[φ_static] = 0. ↓ Proved Since 𝒪_B is quadratic in B^μ ∂_μ L_α, its first variation on a static configuration also vanishes. ↓ Proved The static mass and static equations of motion are unchanged to first order.

The Rotor Matrix Element

Under a rigid rotation, the convective derivative 𝒟 = ∂_t + v·∇ rotates the spatial covector index of L_i:

𝒟 L_i = −(∂_i v^j) L_j = −ω_i^j L_j

After angular integration,

∫ d³x 𝒪_B^(2) = (16π/3) Ω² ∫₀^∞ dr r² ρ(r)² (f’² + 2 sin²f / r²)

Nonzero rotor matrix element

The quadratic rotor matrix element is strictly positive for a nontrivial B = 1 hedgehog.

Part VI — The Non-Redundancy Test

The Redundancy Question

An operator can fail to change the physics if it is a total derivative, proportional to the equations of motion, or removable by a field redefinition. The question is whether

𝒪_B = E_A Y^A + ∂_μ V^μ

The On-Shell Test

Evaluate on the true adiabatic rotating solution φ_Ω = φ₀ + Ω Z_rot + Ω² η₂ + ⋯. Because 𝒪_B[φ₀] = 0 and D𝒪_B[φ₀] = 0, the quadratic matrix element is determined entirely by the rotational zero mode. The centrifugal correction η₂ does not contribute.

Suppose for contradiction that 𝒪_B = E_A Y^A + ∂_μ V^μ. On-shell, E_A = 0, so 𝒪_B = ∂_μ V^μ. Integrating over a closed rotational period T:

∫₀^T dt ∫ d³x ∂_μ V^μ = [∫ d³x V⁰]₀^T + ∫₀^T dt ∮_∞ dS_i V^i

The spatial boundary term vanishes by localization. The temporal term vanishes for single-valued local V⁰ over a closed orbit. Therefore redundancy would imply ∫₀^T dt ∫ d³x 𝒪_B = 0. But the explicit matrix element is TC Ω² + O(Ω³), nonzero.

Nonredundancy proved

𝒪_B ∉ ⟨E_A⟩ + dΩ³_loc

Part VII — The Neutral Result

The Lemma

Metric-independent topological-current non-protection lemma

For an SU(2) hedgehog whose electromagnetic coupling is supplied by a metric-independent topological current B^μ, current–metric locking cannot be protected solely by topology against arbitrary local Lorentz- and symmetry-preserving EFT deformations.

The proof is constructive. The operator 𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α) is local, symmetry-preserving, vanishes on every static configuration, has vanishing first static variation, has a strictly positive quadratic rotor matrix element, and is nonredundant by the closed-orbit on-shell argument.

The Stated Assumptions

AssumptionRole
U is neutral under the electromagnetic U(1)Ensures the deformation does not induce an explicit A_μ dependence.
J_EM^μ = q_t B^μDefines the metric-independent current.
Adiabatic on-shell expansion is validJustifies evaluating on the slowly rotating solution.
Standard locality and falloffEnsures the boundary terms vanish.

Part VIII — The Charged Case

The Setup

If U is charged under the electromagnetic U(1), then J_EM^μ is a Noether current, not a topological current. The neutral-case deformation 𝒪_B does not directly apply. The natural generalization is

𝒪_c = ℬ^μ ℬ^ν Tr(∇_μ L_α ∇_ν L^α)

ℬ^μ is the gauge-invariant baryon current, L_μ = U^† D_μ U.

where the gauge-invariant baryon current must be derived from a fixed gauged action, not selected independently.

The Calculation in Hessian Form

Define two tangent directions in field space:

Z_Ω = ∂(U,A)/∂Ω |₀, Z_B = ∂(U,A)/∂B_ext |₀

The quantities we need are components of the second variation:

δΛ = D²S_c[Z_Ω, Z_Ω], e δκ = D²S_c[Z_Ω, Z_B]

Isotropy forces

D²S_c[Z_{Ω_i}, Z_{Ω_j}] = δ_ij ∫ dr W_Λ

D²S_c[Z_{Ω_i}, Z_{B_j}] = δ_ij ∫ dr W_κ

The Corrected Power Counting

For 𝒪_c = ℬ^μ ℬ^ν X_{μν} with X_{μν} = Tr(∇_μ L_α ∇_ν L^α), the background has ℬ^μ = (ρ, 0) and X₀₀ = 0. Therefore the mixed variation is

δ_B δ_Ω 𝒪_c = δ_B δ_Ω(ℬ^μ ℬ^ν X_{μν})

Because X₀₀^(0) = 0 and δ_Ω X₀₀ = 0, a large class of terms involving δ_B ℬ⁰ dies automatically. The potentially surviving pieces have the schematic form

2ρ (δ_Ω ℬ^i)(δ_B X_{0i}) + 2ρ (δ_B ℬ^i)(δ_Ω X_{0i}) + 2ρ δ_B δ_Ω X₀₀

plus any genuine mixed variation 2ρ (δ_B δ_Ω ℬ^i) X^(0)_{0i}, which itself vanishes if X^(0)_{0i} = 0.

Correction to earlier power counting

Terms containing two rotational ∂₀L’s cannot contribute to the mixed Hessian at B = Ω = 0. The corrected counting is much smaller than the earlier expansion suggested.

The Intermediate Algebraic Test

Before deriving the full radial kernel, perform the intermediate test:

D²S_c[Z_Ω, Z_B] ≟ 0

using only covariance, hedgehog symmetry, and the background identities. If it vanishes identically, Gate 1 collapses to ΔW = −λ W_Λ, and the charged counterexample becomes dramatically simpler. If it does not vanish, only then derive the complete W_κ[f].

Part IX — The Proof Pipeline

The Remaining Gates

Gate 1 Compute the gauge-invariant B_ext Ω coefficient. Derive the gauge-invariant baryon current from a fixed gauged action. Compute the mixed Hessian D²S_c[Z_Ω, Z_B]. Test whether it vanishes identically by symmetry. If not, derive W_κ[f] and run the Euler/jet-space test. Open Gate 2 Prove nonredundancy in the gauged EOM/IBP quotient. Work at A_ext = 0, include the self-field A_μ^self[Ω], and use the closed-orbit argument on the complete coupled solution. Open

The IBP/EOM Test

Define ΔW[f] = W_κ[f] − λ W_Λ[f]. First test whether ΔW is a pure total derivative by taking its one-dimensional Euler operator:

ℰ_f(ΔW) = ∂ΔW/∂f − D_r(∂ΔW/∂f’) + D_r²(∂ΔW/∂f”) − ⋯

Every total derivative satisfies ℰ_f(D_r F) = 0. So if ℰ_f(ΔW) ≠ 0, pure IBP equivalence is excluded. Then test the stronger quotient ΔW ∼ 0 (mod E_f), which becomes a differential-algebra problem in the jet variables (r, f, f’, f”, f”’, …).

The Current Status

ClaimStatus
Neutral topological-current non-protection lemmaProved
Gauged baryon current must be derived from fixed actionCorrected
W_Λ known in neutral limitDerived
W_κ must be explicitly derivedOpen
Mixed Hessian may vanish identically by symmetryTo be tested
IBP test via Euler operatorDefined
EOM test via local jet-space identityDefined
Gauged nonredundancy via full coupled closed-orbit solutionOpen
Ordinary gauge-invariance protectionOpen

Closing State

The neutral topological-current branch is closed. The metric-independent-current non-protection lemma is proved under the stated assumptions. The profile-preserving operator is explicit, local, symmetry-preserving, nonredundant, and has a strictly positive rotor matrix element.

The charged case is open, but the calculation is now sharply defined. The next step is not a vague search for a bosonic mechanism. It is a specific algebraic test: determine whether the mixed Hessian D²S_c[Z_Ω, Z_B] vanishes identically for the properly gauged operator. If it does, the charged counterexample is immediate. If it does not, derive W_κ[f] and test the local jet-space identity modulo IBP and EOM.

The next calculation

Determine whether D²S_c[Z_Ω, Z_B] vanishes identically by symmetry and covariance. If yes, the charged non-protection result follows. If no, compute W_κ[f] for a properly conserved gauged baryon current and test W_κ − λW_Λ modulo IBP/EOM.

What Remains Open

  1. The gauge-invariant baryon current. Must be derived from a fixed gauged action, not selected independently.
  2. The mixed Hessian. D²S_c[Z_Ω, Z_B] has not been computed.
  3. The radial kernel W_κ[f]. Not yet derived.
  4. The IBP/EOM quotient. The local jet-space identity has not been tested.
  5. Gauged nonredundancy. Requires the full coupled closed-orbit solution including the self-field.
  6. Ordinary gauge protection. Whether gauge invariance alone can enforce current–metric locking is open.
  7. Exceptional structures. SUSY, hidden symmetries, and non-generic geometric constructions have not been classified.

The Honest Summary

The derivation produced one clean negative result and one sharply defined open problem. The negative result: a metric-independent topological electromagnetic current cannot, by topology alone, protect current–metric locking. The open problem: whether ordinary gauge invariance can protect it in the charged case, and if not, what exceptional structure could.

The problem is no longer “find a clever soliton profile that gives g = 2.” It is: does there exist a microscopic identity whose local response content forces the electromagnetic magnetic-response functional and the rotational kinetic functional to be the same functional up to q/M?

Record of a derivation. Proved results labeled as proved. Conditional results labeled as conditional. Ruled-out candidates listed with their obstructions. Corrections recorded alongside the claims they correct. Open problems listed with their precise calculation pipelines.

Current–Metric Locking: The Topological-Current Route and the Charged-Case Boundary

Current–Metric Locking: The Topological-Current Route and the Charged-Case Boundary

A record of the derivation from structural g = 2 to the metric-independent topological-current non-protection lemma, and the precise boundary where the charged case remains open. Three epistemic levels kept separate throughout.

How to Read This Document

This is a record of a sustained derivation. It begins from the structural condition Mκ = Λ implied by g = 2 and follows the topological-current route as far as it goes. The neutral case is closed. The charged case is open, with a precise calculation pipeline. Every claim is labeled: proved, derived, conditional, ruled out, or open.

Labels used throughout.
LabelMeaning
ProvedFully established by an explicit construction or a closed argument.
DerivedFollows from a calculation under stated assumptions.
ConditionalHolds only under assumptions not yet verified in general.
Ruled outContradicted by an explicit counterexample or a no-go argument.
OpenNo calculation has settled it.
CorrectedAn earlier claim in the derivation that was found to be wrong.

The Three Epistemic Levels

The main thing worth preserving from this derivation is that there are now three distinct epistemic levels, and they should not be collapsed later.

LevelContent
ProvedMetric-independent topological-current protection fails under the stated neutral-case assumptions.
Open but reducedOrdinary charged bosonic protection, beginning with the mixed Hessian D²S_c[Z_Ω, Z_B].
Open generallyExistence of any purely bosonic exceptional structure that enforces structural g = 2.

These three levels correspond to three different kinds of statement: a closed negative theorem, a reduced calculation with explicit pass/fail gates, and an open classification problem. The document keeps them separate throughout.

Part I — The Sharpened Condition

From Mκ = Λ to Current–Metric Locking

The starting point is structural g = 2 for a charged rotating soliton. In collective-coordinate language, the magnetic moment κ and the moment of inertia Λ satisfy

M κ = Λ

The structural g = 2 condition.

This is equivalent to a mixed-response statement. Writing the energy as

E(B, Ω) = M + ½ Λ Ω² − q κ Ω·B + ⋯

the condition becomes

∂²E/∂Ω_i∂B_j |₀ = −(q/M) ∂²E/∂Ω_i∂Ω_j |₀

The sharpening is to ask what this requires of the moduli-space geometry. Rotation acts through rotational Killing vectors K_i^a. Electromagnetism acts through a U(1) connection whose magnetic response one-form is Θ_EM^i. The moment of inertia is Λ_ij = g_ab K_i^a K_j^b.

Derived Structural g = 2 is equivalent to Θ_EM^i(K_j) = (q/M) g(K_i, K_j). ↓ Conjectured The stronger geometric condition is Θ_EM^i = (q/M) K_i^♭ on the rotational subbundle. ↓ The target Structural g = 2 requires current–metric locking: the electromagnetic magnetic-response one-form must equal the metric dual of the rotational Killing vector, up to q/M.
The sharpened condition

Θ_EM^i = (q/M) K_i^♭

This is much stronger than Mκ = Λ alone. It identifies a specific one-form on moduli space and demands that it be fixed by the rotational Killing vector. Nothing about topology, Bogomolny saturation, or Kähler geometry alone forces this identification.

Part II — The Neutral Topological-Current Route

The Metric-Independent Topological Current

The most natural candidate for a bosonic mechanism is a soliton whose electromagnetic current is a conserved topological current:

J_EM^μ = q_t B^μ, ∂_μ B^μ = 0

B^μ is the degree current of the SU(2) hedgehog.

If this is the whole story, then Θ_EM is determined entirely by B^μ, independently of the kinetic sector. The question is whether topology can protect the locking condition.

The Off-Shell Test

For the SU(2) hedgehog with unit winding, the topological density B⁰(r) satisfies

4π ∫₀^∞ r² B⁰(r) dr = 1

Topology fixes the normalization.

But the magnetic first moment involves an extra factor of r²:

μ_top = (q_t/3) ⟨r²⟩_B Ω

⟨r²⟩_B = ∫ r² B⁰(r) d³x

Topology does not fix the first moment

The normalization integral ∫ B⁰ d³x is topological. The first moment ∫ r² B⁰ d³x is not. It depends on the profile of B⁰(r), and therefore on the soliton shape.

Part III — The Measure Mismatch in BPS Skyrme

BPS Skyrme

The BPS Skyrme model is the most favorable bosonic soliton to test. Its Lagrangian is

ℒ_BPS = −λ²π⁴ B_μ B^μ − μ² V(U)

Squared baryon current plus a potential.

On a BPS solution the two terms are pointwise equal, so the static mass is

M = 2 λ² π⁴ ∫ ρ_B² d³x

The rotational inertia is

Λ = (4/3) λ² π⁴ ∫ r² ρ_B² d³x

The topological magnetic moment is

𝒦 = (q_t/3) ∫ r² ρ_B d³x

The Missing-Half Condition

The proposed identity for the topological contribution is 𝒦 = (q/2)(Λ/M). Substituting the BPS expressions gives

q_t ⟨r²⟩_{ρ_B} = q ⟨r²⟩_{ρ_B²}

Two different moments of the profile.

The measure mismatch

The left side is the mean-square radius weighted by baryon density. The right side is the mean-square radius weighted by squared baryon density. These are different functionals of the profile.

BPS saturation is not enough

Bogomolny saturation of the BPS Skyrme model does not, by itself, enforce the topological missing-half condition. The potential remains a deformation direction inside the BPS class, and it changes the two moments differently.

Part IV — Failed Deformation Candidates

The Strategy

We need a profile-preserving deformation: a local, Lorentz-invariant, symmetry-preserving operator that

𝒪_*[φ₀] = 0, δ_static 𝒪_*[φ₀] = 0, δ²_Ω 𝒪_* ≠ 0

Such an operator leaves the static soliton and its mass unchanged, while changing the rotational kinetic metric. If it does not couple to A_μ, it also leaves the topological current unchanged.

Failed Candidates

CandidateReason it fails
F(X) with X_{μν} = −½ Tr(L_μ L_ν)No smooth algebraic scalar can satisfy F[U₀] = 0 and δ_rot F ≠ 0.
W = ε^{μνρσ} Tr(L_μ L_ν L_ρ L_σ)Vanishes identically for SU(2): four one-forms in a three-dimensional Lie algebra.
(B^μ ∂_μ B²)²On the spherical rotor, B^i ∂_i B² = 0 because the rotation is tangential to level surfaces of B².
B^μ B^ν Tr(∂_μ L_ν)Identically zero: Tr(L_ν) = 0.
(Tr(L_μ L_ν) ∂^μ B^ν)²Vanishes at O(Ω²) on the hedgehog by symmetry of X_ij and antisymmetry of ∂_i v_j.
The recurring obstruction

All these failures share a common geometric origin. For a spherical hedgehog, the rotation velocity v = Ω × x is tangential, and every invariant radial vector is proportional to n. The contraction v·n vanishes. Meanwhile the only invariant rank-two spatial tensor is symmetric, so it cannot contract with the antisymmetric rotation gradient.

Part V — The Profile-Preserving Deformation

The Surviving Operator

The obstruction is broken by using the derivative of the topological current:

𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α)

L_α = U^{-1} ∂_α U.

This operator is local, Lorentz invariant, and symmetry preserving. It does not couple to A_μ.

Properties

Proved For any static configuration, B^μ = (B⁰, 0, 0, 0) and ∂₀L_α = 0. Therefore 𝒪_B[φ_static] = 0. ↓ Proved Since 𝒪_B is quadratic in B^μ ∂_μ L_α, its first variation on a static configuration also vanishes. ↓ Proved The static mass and static equations of motion are unchanged to first order.

The Rotor Matrix Element

Under a rigid rotation, the convective derivative 𝒟 = ∂_t + v·∇ rotates the spatial covector index of L_i:

𝒟 L_i = −(∂_i v^j) L_j = −ω_i^j L_j

After angular integration,

∫ d³x 𝒪_B^(2) = (16π/3) Ω² ∫₀^∞ dr r² ρ(r)² (f’² + 2 sin²f / r²)

Nonzero rotor matrix element

The quadratic rotor matrix element is strictly positive for a nontrivial B = 1 hedgehog.

No Electromagnetic Response

Because 𝒪_B does not couple to A_μ, and because the topological current J_EM^μ = q_t B^μ is unchanged at linear order, the electromagnetic magnetic-response one-form Θ_EM is unchanged:

δ Θ_EM = 0, δ K^♭ ≠ 0

Part VI — The Non-Redundancy Test

The Redundancy Question

An operator can fail to change the physics if it is a total derivative, proportional to the equations of motion, or removable by a field redefinition. The question is whether

𝒪_B = E_A Y^A + ∂_μ V^μ

The On-Shell Test

Evaluate on the true adiabatic rotating solution φ_Ω = φ₀ + Ω Z_rot + Ω² η₂ + ⋯. Because 𝒪_B[φ₀] = 0 and D𝒪_B[φ₀] = 0, the quadratic matrix element is determined entirely by the rotational zero mode. The centrifugal correction η₂ does not contribute.

Suppose for contradiction that 𝒪_B = E_A Y^A + ∂_μ V^μ. On-shell, E_A = 0, so 𝒪_B = ∂_μ V^μ. Integrating over a closed rotational period T:

∫₀^T dt ∫ d³x ∂_μ V^μ = [∫ d³x V⁰]₀^T + ∫₀^T dt ∮_∞ dS_i V^i

The spatial boundary term vanishes by localization. The temporal term vanishes for single-valued local V⁰ over a closed orbit. Therefore redundancy would imply ∫₀^T dt ∫ d³x 𝒪_B = 0. But the explicit matrix element is TC Ω² + O(Ω³), nonzero.

Nonredundancy proved

𝒪_B ∉ ⟨E_A⟩ + dΩ³_loc

Part VII — The Neutral Result

The Lemma

Metric-independent topological-current non-protection lemma

For an SU(2) hedgehog whose electromagnetic coupling is supplied by a metric-independent topological current B^μ, current–metric locking cannot be protected solely by topology against arbitrary local Lorentz- and symmetry-preserving EFT deformations.

The proof is constructive. The operator 𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α) is local, symmetry-preserving, vanishes on every static configuration, has vanishing first static variation, has a strictly positive quadratic rotor matrix element, and is nonredundant by the closed-orbit on-shell argument.

The Stated Assumptions

AssumptionRole
U is neutral under the electromagnetic U(1)Ensures the deformation does not induce an explicit A_μ dependence.
J_EM^μ = q_t B^μDefines the metric-independent current.
Adiabatic on-shell expansion is validJustifies evaluating on the slowly rotating solution.
Standard locality and falloffEnsures the boundary terms vanish.
The conclusion. What this proves is that a metric-independent topological electromagnetic current cannot, by topology alone, protect current–metric locking. It does not prove that no bosonic mechanism can protect it. It closes one route.

Part VIII — The Charged Case

The Setup

If U is charged under the electromagnetic U(1), then J_EM^μ is a Noether current, not a topological current. The neutral-case deformation 𝒪_B does not directly apply. The natural generalization is

𝒪_c = ℬ^μ ℬ^ν Tr(∇_μ L_α ∇_ν L^α)

ℬ^μ is the gauge-invariant baryon current, L_μ = U^† D_μ U.

where the gauge-invariant baryon current must be derived from a fixed gauged action, not selected independently.

The Calculation in Hessian Form

Define two tangent directions in field space:

Z_Ω = ∂(U,A)/∂Ω |₀, Z_B = ∂(U,A)/∂B_ext |₀

The quantities we need are components of the second variation:

δΛ = D²S_c[Z_Ω, Z_Ω], e δκ = D²S_c[Z_Ω, Z_B]

Isotropy forces

D²S_c[Z_{Ω_i}, Z_{Ω_j}] = δ_ij ∫ dr W_Λ

D²S_c[Z_{Ω_i}, Z_{B_j}] = δ_ij ∫ dr W_κ

The Corrected Power Counting

For 𝒪_c = ℬ^μ ℬ^ν X_{μν} with X_{μν} = Tr(∇_μ L_α ∇_ν L^α), the background has ℬ^μ = (ρ, 0) and X₀₀ = 0. Therefore the mixed variation is

δ_B δ_Ω 𝒪_c = δ_B δ_Ω(ℬ^μ ℬ^ν X_{μν})

Because X₀₀^(0) = 0 and δ_Ω X₀₀ = 0, a large class of terms involving δ_B ℬ⁰ dies automatically. The potentially surviving pieces have the schematic form

2ρ (δ_Ω ℬ^i)(δ_B X_{0i}) + 2ρ (δ_B ℬ^i)(δ_Ω X_{0i}) + 2ρ δ_B δ_Ω X₀₀

plus any genuine mixed variation 2ρ (δ_B δ_Ω ℬ^i) X^(0)_{0i}, which itself vanishes if X^(0)_{0i} = 0.

Correction to earlier power counting

Terms containing two rotational ∂₀L’s cannot contribute to the mixed Hessian at B = Ω = 0. The corrected counting is much smaller than the earlier expansion suggested.

The Intermediate Algebraic Test

Before deriving the full radial kernel, perform the intermediate test:

D²S_c[Z_Ω, Z_B] ≟ 0

using only covariance, hedgehog symmetry, and the background identities. This is the first gate of the charged case.

Part IX — The Proof Pipeline

The Remaining Fork

The mixed Hessian is the first gate. The exact remaining fork is

Case = 0 D²S_c[Z_Ω, Z_B] = 0. This establishes δκ = 0 and δΛ ≠ 0 for the candidate at the response level, which closes Gate 1 very strongly. We would still need Gate 2 — the full gauged nonredundancy proof — to establish that this is a genuine independent EFT deformation rather than an EOM/IBP redundancy. Open Case ≠ 0 D²S_c[Z_Ω, Z_B] ≠ 0. Derive W_κ[f] and test locking modulo IBP/EOM. Open
Important wording point. Even if the mixed Hessian vanishes, the charged counterexample does not immediately follow in the full theorem sense. It would establish

δκ = 0, δΛ ≠ 0

for the candidate at the response level, which closes Gate 1 very strongly. Gate 2 — the full gauged nonredundancy proof — is still required to promote the response mismatch into a genuine independent EFT deformation rather than an EOM/IBP artifact.

The Two Gates

Gate 1 Compute the gauge-invariant B_ext Ω coefficient. Derive the gauge-invariant baryon current from a fixed gauged action. Compute the mixed Hessian D²S_c[Z_Ω, Z_B]. Test whether it vanishes identically by symmetry. If not, derive W_κ[f] and run the Euler/jet-space test. Open Gate 2 Prove nonredundancy in the gauged EOM/IBP quotient. Work at A_ext = 0, include the self-field A_μ^self[Ω], and use the closed-orbit argument on the complete coupled solution. Open

The IBP/EOM Test

Define ΔW[f] = W_κ[f] − λ W_Λ[f]. First test whether ΔW is a pure total derivative by taking its one-dimensional Euler operator:

ℰ_f(ΔW) = ∂ΔW/∂f − D_r(∂ΔW/∂f’) + D_r²(∂ΔW/∂f”) − ⋯

Every total derivative satisfies ℰ_f(D_r F) = 0. So if ℰ_f(ΔW) ≠ 0, pure IBP equivalence is excluded. Then test the stronger quotient ΔW ∼ 0 (mod E_f), which becomes a differential-algebra problem in the jet variables (r, f, f’, f”, f”’, …).

The Conditional Conclusion

If the appropriate mismatch and nonredundancy gates both pass, the result is

ordinary U(1) gauge invariance alone does not protect g = 2

That still leaves theories with additional exact structure untouched: supersymmetry, hidden symmetries, constrained operator algebras, non-generic geometric constructions.

The Current Status

ClaimStatus
Neutral topological-current non-protection lemmaProved
Gauged baryon current must be derived from fixed actionCorrected
W_Λ known in neutral limitDerived
W_κ must be explicitly derivedOpen
Mixed Hessian may vanish identically by symmetryTo be tested
IBP test via Euler operatorDefined
EOM test via local jet-space identityDefined
Gauged nonredundancy via full coupled closed-orbit solutionOpen
Ordinary gauge-invariance protectionOpen
Purely bosonic exceptional structuresOpen generally

Closing State

The neutral topological-current branch is closed. The metric-independent-current non-protection lemma is proved under the stated assumptions. The profile-preserving operator is explicit, local, symmetry-preserving, nonredundant, and has a strictly positive rotor matrix element.

The charged case is open, but the calculation is now sharply defined. The next step is not a vague search for a bosonic mechanism. It is a specific algebraic test: determine whether the mixed Hessian D²S_c[Z_Ω, Z_B] vanishes identically for the properly gauged operator.

The next calculation

Determine whether D²S_c[Z_Ω, Z_B] vanishes identically by symmetry and covariance. If yes, Gate 1 is closed and Gate 2 — gauged nonredundancy — becomes the remaining step. If no, compute W_κ[f] for a properly conserved gauged baryon current and test W_κ − λW_Λ modulo IBP/EOM.

What Remains Open

  1. The gauge-invariant baryon current. Must be derived from a fixed gauged action, not selected independently.
  2. The mixed Hessian. D²S_c[Z_Ω, Z_B] has not been computed.
  3. The radial kernel W_κ[f]. Not yet derived.
  4. The IBP/EOM quotient. The local jet-space identity has not been tested.
  5. Gauged nonredundancy. Requires the full coupled closed-orbit solution including the self-field.
  6. Ordinary gauge protection. Whether gauge invariance alone can enforce current–metric locking is open.
  7. Exceptional structures. SUSY, hidden symmetries, and non-generic geometric constructions have not been classified.

The Honest Summary

The derivation produced one clean negative result and one sharply defined open problem. The negative result: a metric-independent topological electromagnetic current cannot, by topology alone, protect current–metric locking. The open problem: whether ordinary gauge invariance can protect it in the charged case, and if not, what exceptional structure could.

The problem is no longer “find a clever soliton profile that gives g = 2.” It is: does there exist a microscopic identity whose local response content forces the electromagnetic magnetic-response functional and the rotational kinetic functional to be the same functional up to q/M?

The neutral theorem is finished. The general theorem is not. The charged problem has been reduced to a concrete calculation with explicit pass/fail gates. Nothing is being called finished that is not finished.


Record of a derivation. Proved results labeled as proved. Conditional results labeled as conditional. Ruled-out candidates listed with their obstructions. Corrections recorded alongside the claims they correct. Open problems listed with their precise calculation pipelines. The three epistemic levels — proved neutral theorem, reduced charged calculation, open general classification — are kept separate throughout.

Current–Metric Locking: The Complete Derivation

Current–Metric Locking: The Complete Derivation

From structural g = 2 to the non-protection of current–metric locking by ordinary U(1) gauge invariance. Neutral theorem closed. Charged case closed conditional on three technical hypotheses. Exceptional-structure protection remains open.

How to Read This Document

This is a record of a sustained derivation. It begins from the structural condition Mκ = Λ implied by g = 2 and follows the topology and gauge routes as far as they go. The neutral case is closed. The charged case is closed conditional on three technical hypotheses. The exceptional-structure question remains open. Every claim is labeled: proved, derived, conditional, ruled out, or open.

Labels used throughout.
LabelMeaning
ProvedFully established by an explicit construction or a closed argument.
DerivedFollows from a calculation under stated assumptions.
ConditionalHolds only under assumptions not yet verified in general.
Ruled outContradicted by an explicit counterexample or a no-go argument.
OpenNo calculation has settled it.
CorrectedAn earlier claim in the derivation that was found to be wrong.

The Three Epistemic Levels

The main thing worth preserving from this derivation is that there are now three distinct epistemic levels, and they should not be collapsed later.

LevelContent
ProvedMetric-independent topological-current protection fails under the stated neutral-case assumptions.
ConditionalOrdinary charged bosonic protection fails, conditional on three technical hypotheses.
Open generallyExistence of any purely bosonic exceptional structure that enforces structural g = 2.

Part I — The Sharpened Condition

From Mκ = Λ to Current–Metric Locking

The starting point is structural g = 2 for a charged rotating soliton. In collective-coordinate language, the magnetic moment κ and the moment of inertia Λ satisfy

M κ = Λ

The structural g = 2 condition.

This is equivalent to a mixed-response statement. Writing the energy as

E(B, Ω) = M + ½ Λ Ω² − q κ Ω·B + ⋯

the condition becomes

∂²E/∂Ω_i∂B_j |₀ = −(q/M) ∂²E/∂Ω_i∂Ω_j |₀

The sharpening is to ask what this requires of the moduli-space geometry. Rotation acts through rotational Killing vectors K_i^a. Electromagnetism acts through a U(1) connection whose magnetic response one-form is Θ_EM^i. The moment of inertia is Λ_ij = g_ab K_i^a K_j^b.

Derived Structural g = 2 is equivalent to Θ_EM^i(K_j) = (q/M) g(K_i, K_j). ↓ Conjectured The stronger geometric condition is Θ_EM^i = (q/M) K_i^♭ on the rotational subbundle. ↓ The target Structural g = 2 requires current–metric locking: the electromagnetic magnetic-response one-form must equal the metric dual of the rotational Killing vector, up to q/M.
The sharpened condition

Θ_EM^i = (q/M) K_i^♭

This is much stronger than Mκ = Λ alone. It identifies a specific one-form on moduli space and demands that it be fixed by the rotational Killing vector. Nothing about topology, Bogomolny saturation, or Kähler geometry alone forces this identification.

Part II — The Neutral Topological-Current Route

The Metric-Independent Topological Current

The most natural candidate for a bosonic mechanism is a soliton whose electromagnetic current is a conserved topological current:

J_EM^μ = q_t B^μ, ∂_μ B^μ = 0

B^μ is the degree current of the SU(2) hedgehog.

If this is the whole story, then Θ_EM is determined entirely by B^μ, independently of the kinetic sector. The question is whether topology can protect the locking condition.

The Off-Shell Test

For the SU(2) hedgehog with unit winding, the topological density B⁰(r) satisfies

4π ∫₀^∞ r² B⁰(r) dr = 1

Topology fixes the normalization.

But the magnetic first moment involves an extra factor of r²:

μ_top = (q_t/3) ⟨r²⟩_B Ω

⟨r²⟩_B = ∫ r² B⁰(r) d³x

Topology does not fix the first moment

The normalization integral ∫ B⁰ d³x is topological. The first moment ∫ r² B⁰ d³x is not. It depends on the profile of B⁰(r), and therefore on the soliton shape.

Part III — The Measure Mismatch in BPS Skyrme

BPS Skyrme

The BPS Skyrme model is the most favorable bosonic soliton to test. Its Lagrangian is

ℒ_BPS = −λ²π⁴ B_μ B^μ − μ² V(U)

Squared baryon current plus a potential.

On a BPS solution the two terms are pointwise equal, so the static mass is

M = 2 λ² π⁴ ∫ ρ_B² d³x

The rotational inertia is

Λ = (4/3) λ² π⁴ ∫ r² ρ_B² d³x

The topological magnetic moment is

𝒦 = (q_t/3) ∫ r² ρ_B d³x

The Missing-Half Condition

The proposed identity for the topological contribution is 𝒦 = (q/2)(Λ/M). Substituting the BPS expressions gives

q_t ⟨r²⟩_{ρ_B} = q ⟨r²⟩_{ρ_B²}

Two different moments of the profile.

The measure mismatch

The left side is the mean-square radius weighted by baryon density. The right side is the mean-square radius weighted by squared baryon density. These are different functionals of the profile.

BPS saturation is not enough

Bogomolny saturation of the BPS Skyrme model does not, by itself, enforce the topological missing-half condition. The potential remains a deformation direction inside the BPS class, and it changes the two moments differently.

Part IV — Failed Deformation Candidates

The Strategy

We need a profile-preserving deformation: a local, Lorentz-invariant, symmetry-preserving operator that

𝒪_*[φ₀] = 0, δ_static 𝒪_*[φ₀] = 0, δ²_Ω 𝒪_* ≠ 0

Such an operator leaves the static soliton and its mass unchanged, while changing the rotational kinetic metric. If it does not couple to A_μ, it also leaves the topological current unchanged.

Failed Candidates

CandidateReason it fails
F(X) with X_{μν} = −½ Tr(L_μ L_ν)No smooth algebraic scalar can satisfy F[U₀] = 0 and δ_rot F ≠ 0.
W = ε^{μνρσ} Tr(L_μ L_ν L_ρ L_σ)Vanishes identically for SU(2): four one-forms in a three-dimensional Lie algebra.
(B^μ ∂_μ B²)²On the spherical rotor, B^i ∂_i B² = 0 because the rotation is tangential to level surfaces of B².
B^μ B^ν Tr(∂_μ L_ν)Identically zero: Tr(L_ν) = 0.
(Tr(L_μ L_ν) ∂^μ B^ν)²Vanishes at O(Ω²) on the hedgehog by symmetry of X_ij and antisymmetry of ∂_i v_j.
The recurring obstruction

All these failures share a common geometric origin. For a spherical hedgehog, the rotation velocity v = Ω × x is tangential, and every invariant radial vector is proportional to n. The contraction v·n vanishes. Meanwhile the only invariant rank-two spatial tensor is symmetric, so it cannot contract with the antisymmetric rotation gradient.

Part V — The Profile-Preserving Deformation

The Surviving Operator

The obstruction is broken by using the derivative of the topological current:

𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α)

L_α = U^{-1} ∂_α U.

This operator is local, Lorentz invariant, and symmetry preserving. It does not couple to A_μ.

Properties

Proved For any static configuration, B^μ = (B⁰, 0, 0, 0) and ∂₀L_α = 0. Therefore 𝒪_B[φ_static] = 0. ↓ Proved Since 𝒪_B is quadratic in B^μ ∂_μ L_α, its first variation on a static configuration also vanishes. ↓ Proved The static mass and static equations of motion are unchanged to first order.

The Rotor Matrix Element

Under a rigid rotation, the convective derivative 𝒟 = ∂_t + v·∇ rotates the spatial covector index of L_i:

𝒟 L_i = −(∂_i v^j) L_j = −ω_i^j L_j

After angular integration,

∫ d³x 𝒪_B^(2) = (16π/3) Ω² ∫₀^∞ dr r² ρ(r)² (f’² + 2 sin²f / r²)

Nonzero rotor matrix element

The quadratic rotor matrix element is strictly positive for a nontrivial B = 1 hedgehog.

No Electromagnetic Response

Because 𝒪_B does not couple to A_μ, and because the topological current J_EM^μ = q_t B^μ is unchanged at linear order, the electromagnetic magnetic-response one-form Θ_EM is unchanged:

δ Θ_EM = 0, δ K^♭ ≠ 0

Part VI — The Non-Redundancy Test

The Redundancy Question

An operator can fail to change the physics if it is a total derivative, proportional to the equations of motion, or removable by a field redefinition. The question is whether

𝒪_B = E_A Y^A + ∂_μ V^μ

The On-Shell Test

Evaluate on the true adiabatic rotating solution φ_Ω = φ₀ + Ω Z_rot + Ω² η₂ + ⋯. Because 𝒪_B[φ₀] = 0 and D𝒪_B[φ₀] = 0, the quadratic matrix element is determined entirely by the rotational zero mode. The centrifugal correction η₂ does not contribute.

Suppose for contradiction that 𝒪_B = E_A Y^A + ∂_μ V^μ. On-shell, E_A = 0, so 𝒪_B = ∂_μ V^μ. Integrating over a closed rotational period T:

∫₀^T dt ∫ d³x ∂_μ V^μ = [∫ d³x V⁰]₀^T + ∫₀^T dt ∮_∞ dS_i V^i

The spatial boundary term vanishes by localization. The temporal term vanishes for single-valued local V⁰ over a closed orbit. Therefore redundancy would imply ∫₀^T dt ∫ d³x 𝒪_B = 0. But the explicit matrix element is TC Ω² + O(Ω³), nonzero.

Nonredundancy proved

𝒪_B ∉ ⟨E_A⟩ + dΩ³_loc

Part VII — The Neutral Result

The Lemma

Metric-independent topological-current non-protection lemma

For an SU(2) hedgehog whose electromagnetic coupling is supplied by a metric-independent topological current B^μ, current–metric locking cannot be protected solely by topology against arbitrary local Lorentz- and symmetry-preserving EFT deformations.

The proof is constructive. The operator 𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α) is local, symmetry-preserving, vanishes on every static configuration, has vanishing first static variation, has a strictly positive quadratic rotor matrix element, and is nonredundant by the closed-orbit on-shell argument.

The Stated Assumptions

AssumptionRole
U is neutral under the electromagnetic U(1)Ensures the deformation does not induce an explicit A_μ dependence.
J_EM^μ = q_t B^μDefines the metric-independent current.
Adiabatic on-shell expansion is validJustifies evaluating on the slowly rotating solution.
Standard locality and falloffEnsures the boundary terms vanish.
The conclusion. What this proves is that a metric-independent topological electromagnetic current cannot, by topology alone, protect current–metric locking. It does not prove that no bosonic mechanism can protect it. It closes one route.

Part VIII — The Charged Case

The Setup

If U is charged under the electromagnetic U(1), then J_EM^μ is a Noether current, not a topological current. The neutral-case deformation 𝒪_B does not directly apply. The natural generalization is

𝒪_c = ℬ^μ ℬ^ν Tr(∇_μ L_α ∇_ν L^α)

ℬ^μ is the gauge-invariant baryon current, L_μ = U^† D_μ U.

where the gauge-invariant baryon current must be derived from a fixed gauged action, not selected independently.

The Calculation in Hessian Form

Define two tangent directions in field space:

Z_Ω = ∂(U,A)/∂Ω |₀, Z_B = ∂(U,A)/∂B_ext |₀

The quantities we need are components of the second variation:

δΛ = D²S_c[Z_Ω, Z_Ω], e δκ = D²S_c[Z_Ω, Z_B]

Isotropy forces

D²S_c[Z_{Ω_i}, Z_{Ω_j}] = δ_ij ∫ dr W_Λ

D²S_c[Z_{Ω_i}, Z_{B_j}] = δ_ij ∫ dr W_κ

Part IX — Gate 1: The Mixed Hessian

The Corrected Expansion

The mixed Hessian is

D²S_c[Z_Ω, Z_B] = δ_Ω δ_B ∫ d⁴x 𝒪_c

On the static background at A = 0: ℬ^μ = (ρ, 0), L₀ = 0, L_i = l_i, X₀₀^(0) = 0, X₀ᵢ^(0) = 0, X_ij^(0) = Tr(l_i l_j).

The Two-Parameter Setup

Introduce two ordinary parameters s, t:

U_{s,t}(x) = A_s(t) U₀(x) A_s^†(t), A_μ = t a_μ^(B)

with A_s^† Ȧ_s = sω and a_i = ½(B_ext × x)_i. Then

D²S_c[Z_Ω, Z_B] = ∂²/∂s∂t ∫ d⁴x 𝒪_c(s,t) |_{s=t=0}

The Vanishing Terms

At s = 0, the configuration is static for all t. Therefore ∇₀ L_i = 0 for all t, and hence

δ_B ∇₀ L_i = ∂_t ∇₀ L_i |_{s=t=0} = 0

The standard gauge-invariant baryon current gives

δ_B ℬ^i = 0

on the static background, for both the Goldstone–Wilczek and Bardeen terms. The mixed Hessian becomes

D²S_c[Z_Ω, Z_B] = 2ρ² Tr(δ_Ω Y_{0α} δ_B Y_0^α) + 2ρ δ_Ω ℬ^i δ_B X_{i0} + 2ρ δ_B ℬ^i δ_Ω X_{i0}

All three terms vanish:

  • The first because δ_B Y_0^α = 0.
  • The second because δ_B X_{i0} = Tr(Y_{iα}^(0) δ_B Y_0^α) = 0.
  • The third because δ_B ℬ^i = 0.
Gate 1 closed

D²S_c[Z_Ω, Z_B] = 0, D²S_c[Z_Ω, Z_Ω] ≠ 0

The vanishing is kinematic. It does not depend on a radial cancellation. It follows from the structure of the mixed Hessian and the staticity of the magnetic tangent.

Correction to the earlier treatment

The earlier implication δ_B X₀₀ = 0 ⇒ δ_Ω δ_B X₀₀ = 0 was invalid. The correct chain uses δ_B Y_{0α} = 0, which follows from the staticity of the magnetic tangent at s = 0. The earlier treatment of δ_Ω ∇₀ L_i = 0 was also wrong: the rotational tangent is not a time-independent isorotation. The corrected argument gives the same result for the right reasons.

Part X — Gate 2: The Continuity Argument

The On-Shell Functional

Let e be the electromagnetic coupling and let

Φ_e(Ω) = (U_e(Ω), A_e(Ω))

be the coupled periodic rotating solution. Define

I(e,Ω) = ∫₀^{T(Ω)} dt ∫ d³x 𝒪_c[Φ_e(Ω)]

For small Ω, I(e,Ω) = T(Ω) C(e) Ω² + O(Ω⁴).

At e = 0, the neutral calculation gives

C(0) = (16π/3) ∫₀^∞ dr r² ρ² (f’² + 2 sin²f / r²) > 0

The Continuity Argument

Assume the coupled rotating branch exists and is continuous near e = 0. Then C(e) → C(0) > 0 as e → 0. Continuity gives ε > 0 such that C(e) ≠ 0 for 0 < |e| < ε.

Suppose 𝒪_c = E_U Y_U + E_A^μ Y_μ + ∂_μ V^μ. On the complete coupled solution, E_U = 0 and E_A^μ = 0. Over one closed collective orbit,

I(e,Ω) = [∫ d³x V⁰]₀^T + ∫₀^T dt ∮_∞ dS_i V^i

With localization, appropriate falloff, and single-valued local V^μ, both terms vanish. Hence redundancy requires I(e,Ω) = 0. But for sufficiently small nonzero e, I(e,Ω) = T C(e) Ω² + O(Ω⁴) ≠ 0. Contradiction.

Gate 2 closed conditionally

𝒪_c ∉ ⟨E_U, E_A^μ⟩ + dΩ³_loc

for an open interval of genuinely nonzero gauge couplings.

The Three Technical Hypotheses

HypothesisStatus
The exact source-derived baryon current gives δ_B ℬ^i = 0 on the static background.Plausible, standard terms vanish
The coupled rotating branch exists and is continuous near e = 0.Standard perturbative assumption
The boundary terms in the closed-orbit argument vanish.Standard falloff assumption

Part XI — The Final Result

The Chain

Proved δM = 0. ↓ Proved δΛ ≠ 0. ↓ Proved δκ = 0. ↓ Conditional 𝒪_c nonredundant in the gauged quotient. ↓ Result D𝒞[𝒪_c] ≠ 0.

The Narrow Statement

Ordinary gauge protection fails

Ordinary U(1) gauge invariance alone does not protect current–metric locking.

The operator 𝒪_c = ℬ^μ ℬ^ν Tr(∇_μ L_α ∇_ν L^α) is a genuine independent EFT deformation that changes the moment of inertia without changing the magnetic moment. The result holds for an open interval of nonzero gauge couplings, which is sufficient to answer the symmetry-protection question.

What This Does Not Prove

It does not prove that structural bosonic g = 2 is impossible. An additional exact symmetry, constrained operator algebra, Ward identity, or geometric structure could still enforce current–metric locking. That exceptional-structure question remains open.

The Current Status

ClaimStatus
Neutral topological-current non-protection lemmaProved
Gauged baryon current must be derived from fixed actionCorrected
W_Λ known in neutral limitDerived
Mixed Hessian D²S_c[Z_Ω, Z_B] = 0Proved kinematically
Gate 1Closed
Gate 2Closed conditional on three hypotheses
Ordinary gauge protectionDisproved
Exceptional-structure protectionOpen generally

Closing State

The neutral topological-current branch is closed. The metric-independent-current non-protection lemma is proved under the stated assumptions. The charged case is closed conditional on three technical hypotheses. The result is that ordinary U(1) gauge invariance alone does not protect current–metric locking.

The only remaining possibility for structural g = 2 in a purely bosonic theory is an additional exact structure: supersymmetry, a hidden symmetry, a constrained operator algebra, a Ward identity, or a non-generic geometric construction. That exceptional-structure question is open.

The next theorem

Classify the local identities capable of enforcing Θ_EM^i = (q/M) K_i^♭ under all allowed deformations, or prove that no purely bosonic structure of this type exists for a charged π₃ soliton.

What Remains Open

  1. The exact source-derived baryon current. The check that δ_B ℬ^i = 0 for the specific gauged action should be completed.
  2. The continuity of the coupled rotating branch. Standard perturbative assumption, but not proved.
  3. The boundary terms. Falloff assumptions should be verified for the specific theory.
  4. Exceptional structures. SUSY, hidden symmetries, constrained operator algebras, and non-generic geometric constructions have not been classified.
  5. The local response identity. The condition ℛ_Θ = (q/M) ℛ_g modulo EOM, total derivatives, and gauge identities has not been classified.

The Honest Summary

The derivation produced two clean negative results and one sharply defined open problem. The negative results: a metric-independent topological electromagnetic current cannot, by topology alone, protect current–metric locking; and ordinary U(1) gauge invariance alone cannot protect it either. The open problem: whether any purely bosonic exceptional structure can.

The problem is no longer “find a clever soliton profile that gives g = 2.” It is: does there exist a microscopic identity whose local response content forces the electromagnetic magnetic-response functional and the rotational kinetic functional to be the same functional up to q/M?

The neutral theorem is finished. The charged theorem is finished conditional on three technical hypotheses. The general theorem is not. Nothing is being called finished that is not finished.


Record of a derivation. Proved results labeled as proved. Conditional results labeled as conditional. Ruled-out candidates listed with their obstructions. Corrections recorded alongside the claims they correct. Open problems listed with their precise calculation pipelines. The three epistemic levels — proved neutral theorem, conditional charged theorem, open general classification — are kept separate throughout.

Current–Metric Locking: The Complete Derivation

Current–Metric Locking: The Complete Derivation

From structural g = 2 to the non-protection of current–metric locking by ordinary U(1) gauge invariance. Neutral theorem proved. Charged case reduced to a finite-dimensional principal-symbol obstruction plus small-coupling persistence. Exceptional-structure protection remains open.

How to Read This Document

This is a record of a sustained derivation. It begins from the structural condition Mκ = Λ implied by g = 2 and follows the topology and gauge routes as far as they go. The neutral case is proved. The charged case is reduced to a principal-symbol obstruction plus a small-coupling persistence argument. The exceptional-structure question remains open.

Labels used throughout.
LabelMeaning
ProvedFully established by an explicit construction or a closed argument.
DerivedFollows from a calculation under stated assumptions.
ConditionalHolds only under assumptions not yet verified in general.
Ruled outContradicted by an explicit counterexample or a no-go argument.
OpenNo calculation has settled it.
CorrectedAn earlier claim in the derivation that was found to be wrong.

The Three Epistemic Levels

The main thing worth preserving from this derivation is that there are now three distinct epistemic levels, and they should not be collapsed later.

LevelContent
ProvedMetric-independent topological-current protection fails under the stated neutral-case assumptions.
ReducedOrdinary charged bosonic protection fails, reduced to a finite-dimensional principal-symbol obstruction plus small-coupling persistence.
Open generallyExistence of any purely bosonic exceptional structure that enforces structural g = 2.

Part I — The Sharpened Condition

From Mκ = Λ to Current–Metric Locking

The starting point is structural g = 2 for a charged rotating soliton. In collective-coordinate language, the magnetic moment κ and the moment of inertia Λ satisfy

M κ = Λ

The structural g = 2 condition.

This is equivalent to a mixed-response statement. Writing the energy as

E(B, Ω) = M + ½ Λ Ω² − q κ Ω·B + ⋯

the condition becomes

∂²E/∂Ω_i∂B_j |₀ = −(q/M) ∂²E/∂Ω_i∂Ω_j |₀

The sharpening is to ask what this requires of the moduli-space geometry. Rotation acts through rotational Killing vectors K_i^a. Electromagnetism acts through a U(1) connection whose magnetic response one-form is Θ_EM^i. The moment of inertia is Λ_ij = g_ab K_i^a K_j^b.

Derived Structural g = 2 is equivalent to Θ_EM^i(K_j) = (q/M) g(K_i, K_j). ↓ Conjectured The stronger geometric condition is Θ_EM^i = (q/M) K_i^♭ on the rotational subbundle. ↓ The target Structural g = 2 requires current–metric locking: the electromagnetic magnetic-response one-form must equal the metric dual of the rotational Killing vector, up to q/M.
The sharpened condition

Θ_EM^i = (q/M) K_i^♭

This is much stronger than Mκ = Λ alone. It identifies a specific one-form on moduli space and demands that it be fixed by the rotational Killing vector. Nothing about topology, Bogomolny saturation, or Kähler geometry alone forces this identification.

Part II — The Neutral Route and Its Closure

The Metric-Independent Topological Current

The most natural candidate for a bosonic mechanism is a soliton whose electromagnetic current is a conserved topological current:

J_EM^μ = q_t B^μ, ∂_μ B^μ = 0

B^μ is the degree current of the SU(2) hedgehog.

The Off-Shell Test

For the SU(2) hedgehog with unit winding, the topological density B⁰(r) satisfies

4π ∫₀^∞ r² B⁰(r) dr = 1

Topology fixes the normalization.

But the magnetic first moment involves an extra factor of r²:

μ_top = (q_t/3) ⟨r²⟩_B Ω

⟨r²⟩_B = ∫ r² B⁰(r) d³x

Topology does not fix the first moment

The normalization integral ∫ B⁰ d³x is topological. The first moment ∫ r² B⁰ d³x is not. It depends on the profile of B⁰(r), and therefore on the soliton shape.

The Measure Mismatch in BPS Skyrme

The BPS Skyrme model is the most favorable bosonic soliton to test. Its Lagrangian is

ℒ_BPS = −λ²π⁴ B_μ B^μ − μ² V(U)

On a BPS solution the two terms are pointwise equal, so the static mass is

M = 2 λ² π⁴ ∫ ρ_B² d³x

The rotational inertia is

Λ = (4/3) λ² π⁴ ∫ r² ρ_B² d³x

The topological magnetic moment is

𝒦 = (q_t/3) ∫ r² ρ_B d³x

The missing-half condition 𝒦 = (q/2)(Λ/M) becomes

q_t ⟨r²⟩_{ρ_B} = q ⟨r²⟩_{ρ_B²}

Two different moments of the profile.

BPS saturation is not enough

Bogomolny saturation of the BPS Skyrme model does not, by itself, enforce the topological missing-half condition. The potential remains a deformation direction inside the BPS class, and it changes the two moments differently.

Failed Deformation Candidates

CandidateReason it fails
F(X) with X_{μν} = −½ Tr(L_μ L_ν)No smooth algebraic scalar can satisfy F[U₀] = 0 and δ_rot F ≠ 0.
W = ε^{μνρσ} Tr(L_μ L_ν L_ρ L_σ)Vanishes identically for SU(2): four one-forms in a three-dimensional Lie algebra.
(B^μ ∂_μ B²)²On the spherical rotor, B^i ∂_i B² = 0 because the rotation is tangential to level surfaces of B².
B^μ B^ν Tr(∂_μ L_ν)Identically zero: Tr(L_ν) = 0.
(Tr(L_μ L_ν) ∂^μ B^ν)²Vanishes at O(Ω²) on the hedgehog by symmetry of X_ij and antisymmetry of ∂_i v_j.

The Profile-Preserving Deformation

The obstruction is broken by using the derivative of the topological current:

𝒪_B = B^μ B^ν Tr(∂_μ L_α ∂_ν L^α)

L_α = U^{-1} ∂_α U.

Proved For any static configuration, B^μ = (B⁰, 0, 0, 0) and ∂₀L_α = 0. Therefore 𝒪_B[φ_static] = 0. ↓ Proved Since 𝒪_B is quadratic in B^μ ∂_μ L_α, its first variation on a static configuration also vanishes. ↓ Proved The static mass and static equations of motion are unchanged to first order.

Under a rigid rotation, the convective derivative rotates the spatial covector index of L_i:

𝒟 L_i = −(∂_i v^j) L_j = −ω_i^j L_j

After angular integration,

∫ d³x 𝒪_B^(2) = (16π/3) Ω² ∫₀^∞ dr r² ρ(r)² (f’² + 2 sin²f / r²)

The Neutral Non-Redundancy Proof

Evaluate on the true adiabatic rotating solution φ_Ω = φ₀ + Ω Z_rot + Ω² η₂ + ⋯. Because 𝒪_B[φ₀] = 0 and D𝒪_B[φ₀] = 0, the quadratic matrix element is determined entirely by the rotational zero mode.

Suppose for contradiction that 𝒪_B = E_A Y^A + ∂_μ V^μ. On-shell, E_A = 0, so 𝒪_B = ∂_μ V^μ. Integrating over a closed rotational period T:

∫₀^T dt ∫ d³x ∂_μ V^μ = [∫ d³x V⁰]₀^T + ∫₀^T dt ∮_∞ dS_i V^i

The spatial boundary term vanishes by localization. The temporal term vanishes for single-valued local V⁰ over a closed orbit. Therefore redundancy would imply ∫₀^T dt ∫ d³x 𝒪_B = 0. But the explicit matrix element is TC Ω² + O(Ω³), nonzero.

Metric-independent topological-current non-protection lemma

For an SU(2) hedgehog whose electromagnetic coupling is supplied by a metric-independent topological current B^μ, current–metric locking cannot be protected solely by topology against arbitrary local Lorentz- and symmetry-preserving EFT deformations.

𝒪_B ∉ ⟨E_A⟩ + dΩ³_loc

Part III — The Charged Case

The Setup

If U is charged under the electromagnetic U(1), then J_EM^μ is a Noether current, not a topological current. The natural generalization is

𝒪_c = ℬ^μ ℬ^ν Tr(∇_μ L_α ∇_ν L^α)

ℬ^μ is the gauge-invariant baryon current, L_μ = U^† D_μ U.

where the gauge-invariant baryon current must be derived from a fixed gauged action.

The Calculation in Hessian Form

Define two tangent directions in field space:

Z_Ω = ∂(U,A)/∂Ω |₀, Z_B = ∂(U,A)/∂B_ext |₀

The quantities we need are components of the second variation:

δΛ = D²S_c[Z_Ω, Z_Ω], e δκ = D²S_c[Z_Ω, Z_B]

Isotropy forces

D²S_c[Z_{Ω_i}, Z_{Ω_j}] = δ_ij ∫ dr W_Λ

D²S_c[Z_{Ω_i}, Z_{B_j}] = δ_ij ∫ dr W_κ

Part IV — Gate 1: The Mixed Hessian

The Corrected Expansion

On the static background at A = 0: ℬ^μ = (ρ, 0), L₀ = 0, L_i = l_i, X₀₀^(0) = 0, X₀ᵢ^(0) = 0, X_ij^(0) = Tr(l_i l_j).

Introduce two ordinary parameters s, t:

U_{s,t}(x) = A_s(t) U₀(x) A_s^†(t), A_μ = t a_μ^(B)

with A_s^† Ȧ_s = sω and a_i = ½(B_ext × x)_i. Then

D²S_c[Z_Ω, Z_B] = ∂²/∂s∂t ∫ d⁴x 𝒪_c(s,t) |_{s=t=0}

At s = 0, the configuration is static for all t. Therefore ∇₀ L_i = 0 for all t, and hence δ_B ∇₀ L_i = 0. The standard gauge-invariant baryon current gives δ_B ℬ^i = 0 on the static background. The mixed Hessian becomes

D²S_c[Z_Ω, Z_B] = 2ρ² Tr(δ_Ω Y_{0α} δ_B Y_0^α) + 2ρ δ_Ω ℬ^i δ_B X_{i0} + 2ρ δ_B ℬ^i δ_Ω X_{i0}

All three terms vanish. The first because δ_B Y_0^α = 0. The second because δ_B X_{i0} = Tr(Y_{iα}^(0) δ_B Y_0^α) = 0. The third because δ_B ℬ^i = 0.

Gate 1 closed

D²S_c[Z_Ω, Z_B] = 0, D²S_c[Z_Ω, Z_Ω] ≠ 0

The vanishing is kinematic. It follows from the structure of the mixed Hessian and the staticity of the magnetic tangent.

Correction to the earlier treatment

The earlier implication δ_B X₀₀ = 0 ⇒ δ_Ω δ_B X₀₀ = 0 was invalid. The correct chain uses δ_B Y_{0α} = 0, which follows from the staticity of the magnetic tangent at s = 0. The earlier treatment of δ_Ω ∇₀ L_i = 0 was also wrong: the rotational tangent is not a time-independent isorotation. The corrected argument gives the same result for the right reasons.

Part V — The Source-Derived Current

The Fixed Action

Fix the action:

S = S_Sk[U,A] + S_Maxwell[A] + S_gWZ[U,A,ℬ_μ]

where ℬ_μ is a background source for baryon number. The gauge-invariant baryon current is defined by

ℬ^μ_GI = δS_gWZ/δℬ_μ |_{ℬ=0}

The standard descent gives

ℬ^μ_GI = B^μ + (e/8π²) ε^{μνρσ} ∂_ν[A_ρ Tr(QL_σ)] + (1/16π²) ε^{μνρσ} A_ν F_{ρσ} Tr(Q²) + O(A²,∂A)

Variation on the Static Background

At A = 0, the background is static: L₀ = 0, and ∂₀ of any static quantity is zero.

Goldstone–Wilczek term

δ_B ℬ^i_GW = (e/8π²) ε^{iνkσ} ∂_ν Tr(QL_σ) |_{A=0}

For the epsilon tensor to be nonzero, i, k, σ, ν must be distinct. Since i, k, σ are spatial, ν = 0. Then ∂₀ of a static quantity vanishes.

δ_B ℬ^i_GW = 0

Bardeen term

δ_B ℬ^i_Bardeen = (1/16π²) ε^{iνρσ} [δA_ν F_{ρσ} + A_ν δF_{ρσ}] Tr(Q²) |_{A=0}

At A = 0, both A_ν = 0 and F_{ρσ} = 0, so both terms vanish.

Source-derived current check

δ_B ℬ^i = 0 for the GW+Bardeen current derived from the fixed gWZ action.

This is the current of a specific action, not an arbitrary ansatz. The index structure excludes local gauge-invariant improvements.

Part VI — Gate 2: The Principal-Symbol Test

Reduction to a Local Test

The closed-orbit argument does not carry over to the zero-frequency adiabatic setting, because the collective configuration is not an exact four-dimensional solution. The correct local test is the off-shell jet-space identity:

𝒪_c – E_A Y^A – ∂_μ V^μ ≡ 0

The best first attack is the principal time-derivative symbol.

The Quadratic Symbol of 𝒪_c

Write U = U₀e^ξ, so δL_μ = D_μξ. At principal order δL_μ ≈ ∂_μξ. On a static background, B^μ = (ρ, 0). For a plane-wave fluctuation ξ = v e^{-iωt+ikz},

δL_0 ≈ -iωv, δL_3 ≈ ikv

Therefore

P_c(ω,k) ∝ ρ² ω²(ω² − k²) 1

Correction to the earlier symbol counting

The quadratic principal symbol of 𝒪_c is not only p₀²|p|². The α = 0 term contributes a p₀⁴ piece. This was invisible in the rigid-rotor calculation because there L₀ = O(Ω) and its convective derivative is O(Ω²). For arbitrary high-frequency fluctuations it must be retained.

The Skyrme Characteristic Matrix at p ∥ n

At a point on the hedgehog, choose the spatial 3-axis along n. The background Maurer–Cartan forms have

X_T = sin²f / r², X_R = f’²

Let A be the sigma-model coefficient and C the Skyrme coefficient. For p ∥ n, the principal quadratic form diagonalizes by internal polarization.

H_R(ω,k) = [A + 2CX_T](ω² − k²)

Radial polarization. Characteristic: ω_R² = k².

H_T(ω,k) = [A + C(X_T+X_R)]ω² − [A+CX_T]k²

Transverse polarization. Characteristic: ω_T² = (A+CX_T)/(A+C(X_T+X_R)) k².

Reversal of the earlier expectation

The sigma model alone is luminal: P_c ∝ (ω² − k²), characteristic ω² = k², both vanish simultaneously. The Skyrme term is what splits the transverse cone away from Minkowski while P_c retains the Minkowski factor. The obstruction comes from the Skyrme term.

Part VII — The Transverse Characteristic Obstruction

Evaluation on the Kernel

For the radial mode, ω_R² = k², so P_c(ω_R,k) = 0. No obstruction.

For a transverse characteristic mode,

ω_T² − k² = −CX_R / [A+C(X_T+X_R)] k²

Therefore

v_T† P_c v_T ∝ −ρ² CX_R[A+CX_T] / [A+C(X_T+X_R)]² k⁴|v_T|²

At a generic point of a nontrivial hedgehog, ρ ≠ 0 and X_R = f’² ≠ 0, and with A, C > 0,

v_T† P_c(ω_T,k) v_T ≠ 0

Correction about the hedgehog center

For the standard B = 1 hedgehog, f(r) = π + ar + O(r³), so f'(0) = a can be nonzero. Then X_R → a² and X_T → a², and the baryon density approaches a finite nonzero limit. The obstruction need not disappear at the center. What becomes isotropic there is X_R = X_T, not X_R = 0.

Part VIII — The Divergence Loophole Removed

The Problem with the Integrated Argument

If 𝒪_c = E_A Y^A + ∂_μ V^μ, then on an exact periodic on-shell solution the integrated 𝒪_c would vanish. But the zero-frequency collective configuration is not an exact four-dimensional solution. On it, E_A ≠ 0 at the relevant higher adiabatic order, so the EOM piece and the divergence piece are evaluated on two different configurations. They do not form a contradiction.

The Euler Operator Test

Apply the Euler–Lagrange operator to the proposed identity. Since the Euler operator annihilates local divergences identically,

E_A(∂_μ V^μ) ≡ 0

redundancy requires

E_A(𝒪_c) = E_A(E_B Y^B)

At quadratic order around the static background, if

S_c^(2) = ½ ∫ ξ† P_c(∂) ξ

then its Euler derivative is essentially the formally self-adjoint operator P_c. A divergence has disappeared automatically. For an infinitesimal field redefinition with linearization R, the quadratic EOM-exact contribution has Euler operator

P_red = H† R + R† H

Now the characteristic-kernel argument becomes legitimate without any V^μ. If Hv = 0, then because the Hessian principal symbol is self-adjoint, v†H† = 0. Hence

v† P_red v = 0

But the transverse Skyrme characteristic gives

v_T† P_c v_T ∝ −ρ² CX_R(A+CX_T) / [A+C(X_T+X_R)]² k⁴|v_T|² ≠ 0

Divergence loophole removed

𝒪_c ≠ E_A Y^A + ∂_μ V^μ

The total-divergence loophole is removed by the Euler operator without constructing V^μ. The matter-sector EOM/IBP redundancy is excluded at principal order.

Part IX — Small-Coupling Persistence

The Coupled Principal Matrix

Write the coupled U(1) + Skyrme principal matrix as

𝕙(e,p) = ( H_UU(p)+O(e) O(e) ; O(e) H_AA(p)+O(e) )

At e = 0, the matter and Maxwell blocks decouple. The matter block has the transverse characteristic mode with the nonzero Euler-symbol matrix element.

Perturbation Theory

At a generic point where ρX_R ≠ 0, choose a transverse characteristic root at e = 0. If that root remains regular, ordinary matrix perturbation theory gives

ω_T(e) = ω_T(0) + O(e)

and a continuously varying eigenvector v_T(e). Consequently,

v_T(e)† P_c(e) v_T(e) = v_T(0)† P_c(0) v_T(0) + O(e)

Since the zeroth-order number is nonzero,

v_T(e)† P_c(e) v_T(e) ≠ 0

for sufficiently small e.

The twofold transverse degeneracy at e = 0 is not fatal. One applies degenerate perturbation theory within the two-dimensional subspace. What matters is that the whole transverse characteristic subspace is separated appropriately from the other branches at the chosen generic background point.

Part X — The Final Status

The Chain

Proved δM = 0. ↓ Proved δΛ ≠ 0. ↓ Proved δκ = 0. ↓ Proved 𝒪_c not EOM-redundant at principal order. ↓ Reduced Small-e persistence via matrix perturbation theory. ↓ Result D𝒞[𝒪_c] ≠ 0.

The Narrow Statement

Ordinary gauge protection fails

Ordinary U(1) gauge invariance alone does not protect current–metric locking.

The operator 𝒪_c = ℬ^μ ℬ^ν Tr(∇_μ L_α ∇_ν L^α) is a genuine independent EFT deformation that changes the moment of inertia without changing the magnetic moment.

What This Does Not Prove

It does not prove that structural bosonic g = 2 is impossible. An additional exact symmetry, constrained operator algebra, Ward identity, or geometric structure could still enforce current–metric locking. That exceptional-structure question remains open.

The Status Table

ClaimStatus
Neutral topological-current non-protection lemmaProved
Gate 1: mixed Hessian D²S_c[Z_Ω, Z_B] = 0Proved kinematically
Source-derived current δ_B ℬ^i = 0Proved for GW+Bardeen
Skyrme characteristic matrix at p ∥ nComputed
Transverse characteristic obstructionNonzero
Total-divergence loopholeRemoved by Euler operator
Matter EOM/IBP redundancyExcluded at principal order
Small-e gauged persistenceFinite-dimensional perturbation step
Ordinary gauge protectionDisproved
Exceptional-structure protectionOpen generally

Closing State

The neutral topological-current branch is closed. The charged case is reduced to a finite-dimensional principal-symbol obstruction plus a small-coupling persistence argument. The result is that ordinary U(1) gauge invariance alone does not protect current–metric locking.

The mechanism is exactly the one identified in the principal-symbol calculation: the sigma model alone is luminal and makes P_c vanish on shell; the Skyrme term splits the transverse cone away from Minkowski while P_c retains the Minkowski factor. The obstruction comes from the Skyrme term.

The next theorem

Classify the local identities capable of enforcing Θ_EM^i = (q/M) K_i^♭ under all allowed deformations, or prove that no purely bosonic structure of this type exists for a charged π₃ soliton.

What Remains Open

  1. The local response identity. The condition ℛ_Θ = (q/M) ℛ_g modulo EOM, total derivatives, and gauge identities has not been classified.
  2. Small-e persistence. The perturbation theory argument is standard but should be completed explicitly.
  3. The global/static continuation. Separate from the local cohomological question, needed only if a full soliton theorem is required.
  4. Exceptional structures. SUSY, hidden symmetries, constrained operator algebras, and non-generic geometric constructions have not been classified.
  5. Purely bosonic common structures. Whether any purely bosonic local structure can enforce the locking condition for all admissible deformations is open.

The Honest Summary

The derivation produced two clean negative results and one sharply defined open problem. The negative results: a metric-independent topological electromagnetic current cannot, by topology alone, protect current–metric locking; and ordinary U(1) gauge invariance alone cannot protect it either. The open problem: whether any purely bosonic exceptional structure can.

The problem is no longer “find a clever soliton profile that gives g = 2.” It is: does there exist a microscopic identity whose local response content forces the electromagnetic magnetic-response functional and the rotational kinetic functional to be the same functional up to q/M?

The neutral theorem is finished. The charged theorem is reduced to a finite-dimensional principal-symbol obstruction plus a standard perturbation step. The general theorem is not. Nothing is being called finished that is not finished.


Record of a derivation. Proved results labeled as proved. Reduced results labeled as reduced. Ruled-out candidates listed with their obstructions. Corrections recorded alongside the claims they correct. Open problems listed with their precise calculation pipelines. The three epistemic levels — proved neutral theorem, reduced charged theorem, open general classification — are kept separate throughout.

Current–Metric Locking: The Complete Derivation

Current–Metric Locking: The Complete Derivation

From structural g = 2 to the principal-symbol cohomological obstruction for the specified gauged SU(2) Skyrme theory. Neutral lemma proved. Principal-symbol obstruction reproducible from the present record. Background algebra at the pole now includes the verified \(l_\theta\) value, the invariant \(-\tfrac12\mathrm{Tr}(l_\theta^2) = \sin^2 f\), and the single-chirality phase-lock structure \(e^{if}\tau_-\). Small-e charged theorem conditional on asserted continuation assumptions. Numerical window undetermined. All-e continuation, the general response identity, and exceptional structures are separate open problems.

How to Read This Document

This is a record of a sustained derivation. It begins from the structural condition Mκ = Λ implied by g = 2 and follows the topology and gauge routes to a sharp result. The neutral case is proved. The charged case has a principal-symbol cohomological obstruction that is reproducible from the present record; the small-e existence theorem is conditional on continuation assumptions that are asserted but not displayed. The numerical size of the window is undetermined. The broader questions — all-e continuation, the general response identity, and exceptional structures — are separate open problems.

Labels and Inspectability

Two label systems are used. The first records the logical status of a claim. The second records the evidentiary basis for it. Both matter, and they are not the same thing.

Logical status

LabelMeaning
ProvedFully established by an explicit construction or a closed argument.
DerivedFollows from a calculation under stated assumptions.
ConditionalHolds only under assumptions not yet verified in general.
Ruled outContradicted by an explicit counterexample or a no-go argument.
OpenNo calculation has settled it.
CorrectedAn earlier claim in the derivation that was found to be wrong.

Evidentiary basis

CategoryMeaning
Reproducible-hereSteps displayed in this record, sufficient to reconstruct the claim.
Reproducible from available sourceDerivation or executable output exists and can be inspected.
Asserted-not-inspectableTranscript-reported, recalled, or summarized. Not a premise for further derivation.
OpenNeither a reproducible derivation nor inspectable output exists.

Labels are sticky and per-result. A claim moves category only when the underlying derivation is recovered or the calculation is independently reproduced in this record. Reconstructing one result does not upgrade neighbouring claims.

Summary of Results

Neutral topological-current non-protection lemma

For an SU(2) hedgehog whose electromagnetic coupling is supplied by a metric-independent topological current \(B^\mu\), current–metric locking cannot be protected solely by topology against arbitrary local Lorentz- and symmetry-preserving EFT deformations.

\(\mathcal O_B \notin \langle E_A\rangle + d\Omega^3_{\rm loc}\)

Proved Reproducible-here

Principal-symbol cohomological obstruction

For the specified gauged SU(2) Skyrme theory, with the fixed gauge-invariant baryon-current prescription, the local deformation \(\mathcal O_c\) fails the principal-symbol Euler-operator identity. Consequently \(\mathcal O_c\) is not EOM-redundant at leading symbol order.

\(v_T^\dagger P_{c,\rm prin}(\omega_T,k)v_T \propto -\rho^2\frac{CX_R(A+CX_T)}{[A+C(X_T+X_R)]^2}k^4|v_T|^2 \neq 0\)

Derived Reproducible-here

Pole value of the transverse Maurer–Cartan form

Under the convention \(U_0 = \cos f + i(\tau\cdot n)\sin f\), at the north pole \(\theta = 0\), \(\varphi = 0\):

\(l_\theta|_{\rm pole} = i\left(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2\right).\)

The \(\tau_1\) coefficient is \(\sin f\cos f = \tfrac12\sin 2f\), not \(\tfrac12\sin^2 f\). The invariant check \(-\tfrac12{\rm Tr}(l_\theta^2) = \sin^2 f\) is satisfied by the form above and fails for the \(\tfrac12\sin^2 f\) form. The result is independent of the left- or right-acting Maurer–Cartan convention for the \(\tau_1\) coefficient.

Derived Reproducible-here

Pole phase-lock structure

At the pole, the Cartesian Maurer–Cartan forms are

\(l_x = \tfrac{i}{r}(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2), \qquad l_y = \tfrac{i}{r}(-\sin^2 f\,\tau_1 + \sin f\cos f\,\tau_2).\)

The circular combination is single-chirality and carries phase \(e^{if}\):

\(l_x – i l_y = \tfrac{i\sin f}{r}e^{if}\tau_- = \tfrac{2i\sin f}{r}e^{if}T_-\).

The \(e^{if}\) phase and single chirality are reproducible here. Whether the transcript’s exact string \(2\sin f\,e^{if}\) referred to this coefficient after stripping the conventional \(i/r\) factor remains asserted-not-inspectable.

Derived Reproducible-here

Small-e charged Skyrme non-protection theorem

For the specified gauged SU(2) Skyrme theory, with the fixed gauge-invariant baryon-current prescription, the principal-symbol obstruction of \(\mathcal O_c\) persists from \(e=0\) to all sufficiently small nonzero \(|e|\). The leading deterioration is \(O(e^2)\).

Conditional Asserted-not-inspectable on the coupled-branch continuation and Riesz-projector assumptions.

The e = 0 cohomological anchor is reproducible-here. The continuation portion — existence and smoothness of the coupled rotating branch in e, Fredholm invertibility of the linearized operator on weighted spaces after zero-mode projection — is asserted-not-inspectable. The theorem as a whole inherits the weaker label.

What is not proved.
  • The coupled-branch continuation and Riesz-projector assumptions have not been displayed. The small-e theorem is conditional on them.
  • The numerical size of the small-coupling neighborhood \(\epsilon\) is undetermined.
  • Whether any particular numerical or physical coupling lies inside the window is not established.
  • The “twice the rate” precession claim for the transverse Maurer–Cartan form is not established by the \(e^{if}\) phase-lock result; it requires its own derivation.
  • Whether any purely bosonic exceptional structure can enforce current–metric locking is open.

Part I — The Sharpened Condition

From Mκ = Λ to Current–Metric Locking

The starting point is structural g = 2 for a charged rotating soliton. In collective-coordinate language, the magnetic moment κ and the moment of inertia Λ satisfy

M κ = Λ

The structural g = 2 condition.

This is equivalent to a mixed-response statement. Writing the energy as

E(B, Ω) = M + ½ Λ Ω² − q κ Ω·B + ⋯

the condition becomes

∂²E/∂Ω_i∂B_j |₀ = −(q/M) ∂²E/∂Ω_i∂Ω_j |₀

The sharpening is to ask what this requires of the moduli-space geometry. Rotation acts through rotational Killing vectors \(K_i^a\). Electromagnetism acts through a U(1) connection whose magnetic response one-form is \(\Theta_{\rm EM}^i\). The moment of inertia is \(\Lambda_{ij} = g_{ab}K_i^aK_j^b\).

Derived Structural g = 2 is equivalent to \(\Theta_{\rm EM}^i(K_j) = (q/M) g(K_i, K_j)\). ↓ Conjectured The stronger geometric condition is \(\Theta_{\rm EM}^i = (q/M) K_i^\flat\) on the rotational subbundle. ↓ The target Structural g = 2 requires current–metric locking: the electromagnetic magnetic-response one-form must equal the metric dual of the rotational Killing vector, up to q/M.
The sharpened condition

\(\Theta_{\rm EM}^i = (q/M) K_i^\flat\)

This is much stronger than Mκ = Λ alone. It identifies a specific one-form on moduli space and demands that it be fixed by the rotational Killing vector. Nothing about topology, Bogomolny saturation, or Kähler geometry alone forces this identification.

Part II — The Neutral Route and Its Closure

The Metric-Independent Topological Current

The most natural candidate for a bosonic mechanism is a soliton whose electromagnetic current is a conserved topological current:

\(J_{\rm EM}^\mu = q_t B^\mu, \qquad \partial_\mu B^\mu = 0\)

\(B^\mu\) is the degree current of the SU(2) hedgehog.

The Off-Shell Test

For the SU(2) hedgehog with unit winding, the topological density \(B^0(r)\) satisfies

\(4\pi \int_0^\infty r^2 B^0(r)\, dr = 1\)

Topology fixes the normalization.

But the magnetic first moment involves an extra factor of \(r^2\):

\(\mu_{\rm top} = (q_t/3)\langle r^2\rangle_B \Omega\)

\(\langle r^2\rangle_B = \int r^2 B^0(r)\, d^3x\)

Topology does not fix the first moment

The normalization integral \(\int B^0\, d^3x\) is topological. The first moment \(\int r^2 B^0\, d^3x\) is not. It depends on the profile of \(B^0(r)\), and therefore on the soliton shape.

The Measure Mismatch in BPS Skyrme

The BPS Skyrme model is the most favorable bosonic soliton to test. Its Lagrangian is

\(\mathcal L_{\rm BPS} = -\lambda^2\pi^4 B_\mu B^\mu – \mu^2 V(U)\)

On a BPS solution the two terms are pointwise equal, so the static mass is

\(M = 2\lambda^2\pi^4 \int \rho_B^2\, d^3x\)

The rotational inertia is

\(\Lambda = (4/3)\lambda^2\pi^4 \int r^2\rho_B^2\, d^3x\)

The topological magnetic moment is

\(\mathcal K = (q_t/3)\int r^2\rho_B\, d^3x\)

The missing-half condition \(\mathcal K = (q/2)(\Lambda/M)\) becomes

\(q_t \langle r^2\rangle_{\rho_B} = q \langle r^2\rangle_{\rho_B^2}\)

Two different moments of the profile.

BPS saturation is not enough

Bogomolny saturation of the BPS Skyrme model does not, by itself, enforce the topological missing-half condition. The potential remains a deformation direction inside the BPS class, and it changes the two moments differently.

Failed Deformation Candidates

CandidateReason it fails
\(F(X)\) with \(X_{\mu\nu} = -\tfrac12{\rm Tr}(L_\mu L_\nu)\)No smooth algebraic scalar can satisfy \(F[U_0]=0\) and \(\delta_{\rm rot}F\neq0\).
\(W = \varepsilon^{\mu\nu\rho\sigma}{\rm Tr}(L_\mu L_\nu L_\rho L_\sigma)\)Vanishes identically for SU(2): four one-forms in a three-dimensional Lie algebra.
\((B^\mu\partial_\mu B^2)^2\)On the spherical rotor, \(B^i\partial_i B^2 = 0\) because the rotation is tangential to level surfaces of \(B^2\).
\(B^\mu B^\nu{\rm Tr}(\partial_\mu L_\nu)\)Identically zero: \({\rm Tr}(L_\nu)=0\).
\(({\rm Tr}(L_\mu L_\nu)\partial^\mu B^\nu)^2\)Vanishes at \(O(\Omega^2)\) on the hedgehog by symmetry of \(X_{ij}\) and antisymmetry of \(\partial_i v_j\).
The recurring obstruction

All these failures share a common geometric origin. For a spherical hedgehog, the rotation velocity \(v = \Omega \times x\) is tangential, and every invariant radial vector is proportional to \(n\). The contraction \(v\cdot n\) vanishes. Meanwhile the only invariant rank-two spatial tensor is symmetric, so it cannot contract with the antisymmetric rotation gradient.

The Profile-Preserving Deformation

The obstruction is broken by using the derivative of the topological current:

\(\mathcal O_B = B^\mu B^\nu\,{\rm Tr}(\partial_\mu L_\alpha \partial_\nu L^\alpha)\)

\(L_\alpha = U^{-1}\partial_\alpha U\).

Proved For any static configuration, \(B^\mu = (B^0,0,0,0)\) and \(\partial_0 L_\alpha = 0\). Therefore \(\mathcal O_B[\phi_{\rm static}] = 0\). ↓ Proved Since \(\mathcal O_B\) is quadratic in \(B^\mu\partial_\mu L_\alpha\), its first variation on a static configuration also vanishes. ↓ Proved The static mass and static equations of motion are unchanged to first order.

Under a rigid rotation, the convective derivative rotates the spatial covector index of \(L_i\):

\(\mathcal D L_i = -(\partial_i v^j)L_j = -\omega_i{}^j L_j\)

After angular integration,

\(\int d^3x\,\mathcal O_B^{(2)} = \frac{16\pi}{3}\Omega^2 \int_0^\infty dr\, r^2\rho(r)^2\left(f’^2 + 2\frac{\sin^2 f}{r^2}\right)\)

The Neutral Non-Redundancy Proof

Evaluate on the true adiabatic rotating solution \(\phi_\Omega = \phi_0 + \Omega Z_{\rm rot} + \Omega^2\eta_2 + \cdots\). Because \(\mathcal O_B[\phi_0]=0\) and \(D\mathcal O_B[\phi_0]=0\), the quadratic matrix element is determined entirely by the rotational zero mode.

Suppose for contradiction that \(\mathcal O_B = E_A Y^A + \partial_\mu V^\mu\). On-shell, \(E_A=0\), so \(\mathcal O_B = \partial_\mu V^\mu\). Integrating over a closed rotational period T:

\(\int_0^T dt\int d^3x\,\partial_\mu V^\mu = \left[\int d^3x\,V^0\right]_0^T + \int_0^T dt\oint_\infty dS_i\,V^i\)

The spatial boundary term vanishes by localization. The temporal term vanishes for single-valued local \(V^0\) over a closed orbit. Therefore redundancy would imply \(\int_0^T dt\int d^3x\,\mathcal O_B = 0\). But the explicit matrix element is \(TC\Omega^2 + O(\Omega^3)\), nonzero.

Metric-independent topological-current non-protection lemma

For an SU(2) hedgehog whose electromagnetic coupling is supplied by a metric-independent topological current \(B^\mu\), current–metric locking cannot be protected solely by topology against arbitrary local Lorentz- and symmetry-preserving EFT deformations.

\(\mathcal O_B \notin \langle E_A\rangle + d\Omega^3_{\rm loc}\)

Proved Reproducible-here

Part III — The Charged Case: Setup

The Operator

If U is charged under the electromagnetic U(1), then \(J_{\rm EM}^\mu\) is a Noether current, not a topological current. The natural generalization is

\(\mathcal O_c = \mathcal B^\mu\mathcal B^\nu\,{\rm Tr}(\nabla_\mu L_\alpha \nabla_\nu L^\alpha)\)

\(\mathcal B^\mu\) is the gauge-invariant baryon current, \(L_\mu = U^\dagger D_\mu U\).

where the gauge-invariant baryon current must be derived from a fixed gauged action.

Part IV — Gate 1: The Mixed Hessian

The Corrected Expansion

On the static background at \(A=0\): \(\mathcal B^\mu = (\rho, 0)\), \(L_0=0\), \(L_i=l_i\), \(X_{00}^{(0)}=0\), \(X_{0i}^{(0)}=0\), \(X_{ij}^{(0)}={\rm Tr}(l_i l_j)\).

Introduce two ordinary parameters s, t:

\(U_{s,t}(x) = A_s(t)U_0(x)A_s^\dagger(t), \qquad A_\mu = t\, a_\mu^{(B)}\)

with \(A_s^\dagger\dot A_s = s\omega\) and \(a_i = \tfrac12(B_{\rm ext}\times x)_i\). Then

\(D^2S_c[Z_\Omega, Z_B] = \partial^2/\partial s\,\partial t \int d^4x\,\mathcal O_c(s,t)|_{s=t=0}\)

At \(s=0\), the configuration is static for all t. Therefore \(\nabla_0 L_i = 0\) for all t, and hence \(\delta_B\nabla_0 L_i = 0\). The standard gauge-invariant baryon current gives \(\delta_B\mathcal B^i = 0\) on the static background. The mixed Hessian becomes

\(D^2S_c[Z_\Omega, Z_B] = 2\rho^2{\rm Tr}(\delta_\Omega Y_{0\alpha}\delta_B Y_0{}^\alpha) + 2\rho\,\delta_\Omega\mathcal B^i\,\delta_B X_{i0} + 2\rho\,\delta_B\mathcal B^i\,\delta_\Omega X_{i0}\)

All three terms vanish. The first because \(\delta_B Y_0{}^\alpha = 0\). The second because \(\delta_B X_{i0} = {\rm Tr}(Y_{i\alpha}^{(0)}\delta_B Y_0{}^\alpha) = 0\). The third because \(\delta_B\mathcal B^i = 0\).

Gate 1 closed

\(D^2S_c[Z_\Omega, Z_B] = 0, \qquad D^2S_c[Z_\Omega, Z_\Omega] \neq 0\)

The vanishing is kinematic. It follows from the structure of the mixed Hessian and the staticity of the magnetic tangent.

Proved Reproducible-here

Correction to the earlier treatment

The earlier implication \(\delta_B X_{00}=0 \Rightarrow \delta_\Omega\delta_B X_{00}=0\) was invalid. The correct chain uses \(\delta_B Y_{0\alpha}=0\), which follows from the staticity of the magnetic tangent at s = 0. The earlier treatment of \(\delta_\Omega\nabla_0 L_i = 0\) was also wrong: the rotational tangent is not a time-independent isorotation. The corrected argument gives the same result for the right reasons.

Part V — The Source-Derived Current

The Fixed Action

Fix the action:

\(S = S_{\rm Sk}[U,A] + S_{\rm Maxwell}[A] + S_{\rm gWZ}[U,A,\mathcal B_\mu]\)

where \(\mathcal B_\mu\) is a background source for baryon number. The gauge-invariant baryon current is defined by

\(\mathcal B^\mu_{\rm GI} = \delta S_{\rm gWZ}/\delta\mathcal B_\mu|_{\mathcal B=0}\)

The standard descent gives

\(\mathcal B^\mu_{\rm GI} = B^\mu + \frac{e}{8\pi^2}\varepsilon^{\mu\nu\rho\sigma}\partial_\nu[A_\rho{\rm Tr}(QL_\sigma)] + \frac{1}{16\pi^2}\varepsilon^{\mu\nu\rho\sigma}A_\nu F_{\rho\sigma}{\rm Tr}(Q^2) + O(A^2,\partial A)\)

Variation on the Static Background

At \(A=0\), the background is static: \(L_0=0\), and \(\partial_0\) of any static quantity is zero.

Goldstone–Wilczek term

\(\delta_B\mathcal B^i_{GW} = \frac{e}{8\pi^2}\varepsilon^{i\nu k\sigma}\partial_\nu{\rm Tr}(QL_\sigma)|_{A=0}\)

For the epsilon tensor to be nonzero, \(i,k,\sigma,\nu\) must be distinct. Since \(i,k,\sigma\) are spatial, \(\nu=0\). Then \(\partial_0\) of a static quantity vanishes.

\(\delta_B\mathcal B^i_{GW} = 0\)

Bardeen term

\(\delta_B\mathcal B^i_{\rm Bardeen} = \frac{1}{16\pi^2}\varepsilon^{i\nu\rho\sigma}[\delta A_\nu F_{\rho\sigma} + A_\nu\delta F_{\rho\sigma}]{\rm Tr}(Q^2)|_{A=0}\)

At \(A=0\), both \(A_\nu=0\) and \(F_{\rho\sigma}=0\), so both terms vanish.

Source-derived current check

\(\delta_B\mathcal B^i = 0\) for the GW+Bardeen current derived from the fixed gWZ action.

This is the current of a specific action, not an arbitrary ansatz. The index structure excludes local gauge-invariant improvements.

Proved Reproducible-here

Part VI — The Principal-Symbol Obstruction

Reduction to a Local Test

The closed-orbit argument does not carry over to the zero-frequency adiabatic setting, because the collective configuration is not an exact four-dimensional solution. The correct local test is the off-shell jet-space identity:

\(\mathcal O_c – E_A Y^A – \partial_\mu V^\mu \equiv 0\)

The best first attack is the principal time-derivative symbol.

The Quadratic Symbol of \(\mathcal O_c\)

Write \(U = U_0 e^\xi\), so \(\delta L_\mu = D_\mu\xi\). At principal order \(\delta L_\mu \approx \partial_\mu\xi\). On a static background, \(B^\mu=(\rho,0)\). For a plane-wave fluctuation \(\xi = v\,e^{-i\omega t + ikz}\),

\(\delta L_0 \approx -i\omega v, \qquad \delta L_3 \approx ikv\)

The principal contraction is the Minkowski sum over \(\alpha\):

\(\partial_0\partial_0\xi = -\omega^2\xi, \qquad \partial_0\partial_3\xi = \omega k\,\xi, \qquad \partial_0\partial_{1,2}\xi = 0\)

\({\rm Tr}(\partial_0 L_\alpha\,\partial_0 L^\alpha) \propto \omega^4 – \omega^2 k^2 = \omega^2(\omega^2 – k^2)\)

Therefore

\(P_{c,\rm prin} \propto \rho^2\omega^2(\omega^2 – k^2)|v|^2\)

Correction to the earlier symbol counting

The quadratic principal symbol of \(\mathcal O_c\) is not only \(p_0^2|p|^2\). The \(\alpha=0\) term contributes a \(p_0^4\) piece. This was invisible in the rigid-rotor calculation because there \(L_0=O(\Omega)\) and its convective derivative is \(O(\Omega^2)\). For arbitrary high-frequency fluctuations it must be retained.

The Skyrme Characteristic Matrix at \(p \parallel n\)

At a point on the hedgehog, choose the spatial 3-axis along n. The background Maurer–Cartan forms have

\(X_T = \frac{\sin^2 f}{r^2}, \qquad X_R = f’^2\)

Let A be the sigma-model coefficient and C the Skyrme coefficient. For \(p \parallel n\), the principal quadratic form diagonalizes by internal polarization.

\(H_R(\omega,k) = [A + 2CX_T](\omega^2 – k^2)\)

Radial polarization. Characteristic: \(\omega_R^2 = k^2\).

\(H_T(\omega,k) = [A + C(X_T+X_R)]\omega^2 – [A+CX_T]k^2\)

Transverse polarization. Characteristic: \(\omega_T^2 = \frac{A+CX_T}{A+C(X_T+X_R)}k^2\).

Reversal of the earlier expectation

The sigma model alone is luminal: \(P_{c,\rm prin} \propto (\omega^2 – k^2)\), characteristic \(\omega^2 = k^2\), both vanish simultaneously. The Skyrme term is what splits the transverse cone away from Minkowski while \(P_{c,\rm prin}\) retains the Minkowski factor. The obstruction comes from the Skyrme term.

The Transverse Obstruction

For the radial mode, \(\omega_R^2=k^2\), so \(P_{c,\rm prin}(\omega_R,k)=0\). No obstruction.

For a transverse characteristic mode,

\(\omega_T^2 – k^2 = -\frac{CX_R}{A+C(X_T+X_R)}k^2\)

Therefore

\(v_T^\dagger P_{c,\rm prin} v_T \propto -\rho^2\frac{CX_R[A+CX_T]}{[A+C(X_T+X_R)]^2}k^4|v_T|^2\)

At a generic point of a nontrivial hedgehog, \(\rho \neq 0\) and \(X_R = f’^2 \neq 0\), and with \(A,C > 0\),

\(v_T^\dagger P_{c,\rm prin}(\omega_T,k)v_T \neq 0\)

Derived Reproducible-here

Correction about the hedgehog center

For the standard B = 1 hedgehog, \(f(r) = \pi + ar + O(r^3)\), so \(f'(0) = a\) can be nonzero. Then \(X_R \to a^2\) and \(X_T \to a^2\), and the baryon density approaches a finite nonzero limit. The obstruction need not disappear at the center. What becomes isotropic there is \(X_R = X_T\), not \(X_R = 0\). The \(X_R = 0\) limit is an artificial local diagnostic, not the hedgehog-center limit.

Part VII — The Divergence Loophole Removed

The Problem with the Integrated Argument

If \(\mathcal O_c = E_A Y^A + \partial_\mu V^\mu\), then on an exact periodic on-shell solution the integrated \(\mathcal O_c\) would vanish. But the zero-frequency collective configuration is not an exact four-dimensional solution. On it, \(E_A \neq 0\) at the relevant higher adiabatic order, so the EOM piece and the divergence piece are evaluated on two different configurations. They do not form a contradiction.

The Euler Operator Test

Apply the Euler–Lagrange operator to the proposed identity. Since the Euler operator annihilates local divergences identically,

\(\mathcal E_A(\partial_\mu V^\mu) \equiv 0\)

redundancy requires

\(\mathcal E_A(\mathcal O_c) = \mathcal E_A(E_B Y^B)\)

At quadratic order around the static background, if

\(S_c^{(2)} = \tfrac12\int \xi^\dagger P_c(\partial)\xi\)

then its Euler derivative is essentially the formally self-adjoint operator \(P_c\). A divergence has disappeared automatically. For an infinitesimal field redefinition with linearization R, the quadratic EOM-exact contribution has Euler operator

\(P_{\rm red} = H^\dagger R + R^\dagger H\)

Now the characteristic-kernel argument becomes legitimate without any \(V^\mu\). If \(Hv=0\), then because the Hessian principal symbol is self-adjoint, \(v^\dagger H^\dagger = 0\). Hence

\(v^\dagger P_{\rm red}v = 0\)

But the transverse Skyrme characteristic gives

\(v_T^\dagger P_{c,\rm prin} v_T \propto -\rho^2\frac{CX_R(A+CX_T)}{[A+C(X_T+X_R)]^2}k^4|v_T|^2 \neq 0\)

Divergence loophole removed

\(\mathcal O_c \neq E_A Y^A + \partial_\mu V^\mu\)

The total-divergence loophole is removed by the Euler operator without constructing \(V^\mu\). The matter-sector EOM/IBP redundancy is excluded at principal order. The argument is a full local-cohomology argument, not a high-frequency approximation: an exact operator identity would imply principal-symbol equality at highest homogeneous degree, and that fails.

Derived Reproducible-here

Part VIII — The Gauss-Reduced Physical Pencil

Coulomb Gauge and the Gauss Constraint

Impose the Coulomb gauge condition \(\partial_i A_i = 0\) as a gauge choice. This sets the longitudinal component \(A_L = 0\). The residual gauge freedom is time-independent gauge transformations, fixed by requiring \(A_0 \to 0\) at spatial infinity.

The Gauss constraint is not \(\partial_i\dot A_i = 0\); it is

\(-\nabla^2 A_0 = \rho_{\rm matter}(\xi)\)

where \(\rho_{\rm matter}\) is the linearized charge density of the matter fluctuation. At fixed nonzero spatial momentum k, this gives

\(A_0 = \frac{\rho_{\rm matter}(\xi)}{k^2}\)

So \(A_0\) is a constrained field determined instantaneously by the matter fluctuation. It is not an independent dynamical degree of freedom.

Correction to the earlier gauge-fixing argument

The earlier claim that temporal gauge plus \(\partial_i A_i = 0\) immediately gives the physical sector was too quick. In the coupled charged theory, Gauss’s law is \(\partial_i E_i = J^0_{\rm matter}\), so the longitudinal electric field participates in the constraint and is sourced by \(\xi\). The correct reduction is Coulomb gauge plus solving the Gauss constraint for \(A_0\).

The Physical Degrees of Freedom

After Coulomb gauge fixing and solving Gauss’s law, the physical dynamical fields are

\((\xi^a, A_T^i)\)

with \(\xi\) a three-component matter fluctuation and \(A_T\) the two transverse photon polarizations. Total: five degrees of freedom.

The Physical Pencil

The linearized equations for the physical fields take the form

\(\mathbb H_{\rm phys}(e,\omega,k)v = 0, \qquad \mathbb H_{\rm phys} = \omega^2 K_{\rm phys}(e,k) – S_{\rm phys}(e,k)\)

The kinetic matrix at \(e=0\)

At \(e=0\), the matter and transverse photon sectors decouple. The kinetic matrix is block diagonal:

\(K_{\rm phys}(0,k) = {\rm diag}(K_T, K_T, K_R, 1, 1)\)

\(K_T = A + C(X_T + X_R), \qquad K_R = A + 2CX_T\)

Both are positive since \(A,C > 0\) and \(X_T, X_R \geq 0\). The last two entries are the standard Maxwell kinetic coefficients.

Physical kinetic block

\(K_{\rm phys}(0,k)\) is positive definite and invertible.

Derived Reproducible-here

Continuity in \(e\)

The covariant derivative introduces the coupling \(D_\mu\xi = \partial_\mu\xi – ieA_\mu[Q,\xi]\). At fixed k, the coupling between matter and transverse photons enters at \(O(e)\). The Coulomb backreaction through \(A_0 = \rho_{\rm matter}/k^2\) enters at \(O(e^2)\). Both are bounded on the physical sector for a smooth static background. Therefore

\(K_{\rm phys}(e,k) = K_{\rm phys}(0,k) + O(e), \qquad S_{\rm phys}(e,k) = S_{\rm phys}(0,k) + O(e)\)

Since \(K_{\rm phys}(0,k)\) is positive definite, its eigenvalues are bounded below by a positive constant. Small perturbations preserve invertibility:

\(K_{\rm phys}(e,k)\) is invertible for sufficiently small \(e\).

Part IX — Small-Coupling Persistence (Conditional)

Status of this part. The e = 0 cohomological anchor — Parts IV–VII — is reproducible-here. The continuation argument below is the standard implicit-function-theorem / Riesz-projector argument for a small-e perturbation of a nondegenerate soliton. It is stated in the form in which it would be carried out, but the detailed weighted-space setup, the spectral gap estimates, and the Fredholm invertibility have not been displayed in this record. The argument below is therefore Conditional Asserted-not-inspectable.

The Reduced Matrix

Define

\(\mathbb N(e,k) = K_{\rm phys}(e,k)^{-1}S_{\rm phys}(e,k)\)

This is continuous in \(e\) on the physical sector.

The Spectral Gap at \(e=0\)

At \(e=0\), the transverse matter cluster has eigenvalue

\(\lambda_T = \omega_T^2 = \frac{A+CX_T}{A+C(X_T+X_R)}k^2\)

of multiplicity two, isolated from the radial matter branch and the transverse photon branch by

\(\Delta = \frac{CX_R}{A+C(X_T+X_R)}k^2 > 0\)

The Riesz Projector Argument

Choose a contour \(\Gamma\) surrounding \(\lambda_T\) and no other eigenvalue. Define

\(\Pi_T(e) = \frac{1}{2\pi i}\oint_\Gamma (z – \mathbb N(e,k))^{-1}\,dz\)

For sufficiently small \(e\), \(\Pi_T(e)\) exists, satisfies \(\Pi_T(e) \to \Pi_T(0)\), and has rank 2. Conditional on the asserted continuation

The Quadratic Form on the Cluster

At \(e=0\),

\(P_c(0)|_{{\rm Ran}\,\Pi_T(0)} = \gamma\,\mathbf 1_2\)

\(\gamma \propto -\rho^2\frac{CX_R(A+CX_T)}{[A+C(X_T+X_R)]^2}k^4 \neq 0\)

By continuity,

\(\Pi_T(e)P_c(e)\Pi_T(e) = \gamma\,\Pi_T(e) + O(e)\)

For sufficiently small \(e\), this restricted quadratic form is nondegenerate on the entire perturbed two-dimensional cluster. Conditional on the asserted continuation

What is not displayed here

The coupled static and rotating branch \(\Phi_e(\Omega)\); the linearized operator \(D\mathscr F\) on weighted Sobolev spaces; its Fredholm invertibility after zero-mode projection; the smoothness of the Riesz projector in \(e\). These are the standard elements of the continuation argument, but they have not been reconstructed in this record. Until they are, the small-e theorem is conditional on them.

Part X — The O(e) Block Identities

The Three Identities

The target is

\(K_1^{mm} = 0, \qquad S_1^{mm} = 0, \qquad P_1^{mm} = 0.\)

If all three hold, then

\(N_1 = K_0^{-1}S_1 – K_0^{-1}K_1 N_0\)

is matter–photon off-diagonal, so for every matter vector \(v\),

\(N_1 v \in \mathcal H_\gamma.\)

The first-order correction to a transverse matter eigenvector is purely photonic:

\(w^{(1)} = -Q(N_0 – \lambda_T)^{-1}Q N_1 v \in \mathcal H_\gamma.\)

Then \(P_0 w^{(1)} = 0\) because \(P_0\) acts only on the matter sector, and \(v^\dagger P_1 v = 0\) from the block condition. Therefore

\(v(e)^\dagger P(e)v(e) = \gamma + O(e^2).\)

The Structural Argument for \(K_1^{mm} = S_1^{mm} = 0\)

The quadratic action at \(e=0\) is block diagonal. At \(O(e)\), the only source of coupling is the covariant derivative \(D_\mu U = \partial_\mu U – ie\,a_\mu[Q,U]\). Every explicit \(\partial_e\) at \(e=0\) introduces exactly one gauge fluctuation \(a_\mu\), provided:

  1. The background matter field has no \(O(e)\) displacement.
  2. The background gauge potential starts at \(O(e)\).

Both hold: the Coulomb field \(A_0^{(0)}\) is \(O(e)\), and the profile shift is \(O(e^2)\). Therefore \(H_1\) is block off-diagonal with no matter–matter component.

Gauss reduction. The constrained variable satisfies \(a_0 = e\,G\,\xi + \cdots\). Substituting back produces \(e^2\,\xi G\xi\), not \(e\,\xi^2\). So the Gauss reduction preserves \(H_1^{mm} = 0\).

The \(P_1^{mm}\) Check

The operator is \(\mathcal O_c = \mathcal B^\mu \mathcal B^\nu\,{\rm Tr}(\nabla_\mu L_\alpha \nabla_\nu L^\alpha)\). The expansion of \(L_\mu\) and \(\nabla_\mu L_\alpha\) yields only \(e\,a\xi\) terms at \(O(e)\), never \(e\,\xi^2\). Therefore

\(P_1^{mm} = 0.\)

Conclusion

\(K_1^{mm} = 0, \qquad S_1^{mm} = 0, \qquad P_1^{mm} = 0.\)

Therefore \(\delta\lambda_T^{(1)} = 0\), \(\delta\gamma^{(1)} = 0\), and the leading deterioration is \(O(e^2)\).

The Second-Order Effective Operator

\(N_{\rm eff}(e) = \lambda_T\Pi_T + e^2\left[\Pi_T N_2 \Pi_T – \Pi_T N_1 Q (QN_0Q – \lambda_T)^{-1} Q N_1 \Pi_T\right] + O(e^3).\)

Correction to the description of the second-order problem

The radial–photon degeneracy at \(\lambda_R = \lambda_\gamma = k^2\) is not a singularity in the Schur complement for the transverse cluster. The resolvent is evaluated relative to \(\lambda_T\), and both the radial and photon states have denominator \(k^2 – \lambda_T = \Delta > 0\).

A term schematically written \((ea[Q,\xi])^2\) is not itself a matter–matter term: before eliminating \(a\), it is quartic in fluctuations. Direct \(N_2^{mm}\) terms come from \(O(e^2)\) background Coulomb/profile corrections and from the Gauss-reduced quadratic action.

Part XI — The Window-Size Specification (Draft)

Status of this part. This is a CAS specification draft, not an executable specification. The frozen input is unambiguous. The matrix \(P_{2,\rm explicit}^{mm}\) has not been calculated. Producing it requires a computer algebra system with the \(\mathfrak{su}(2)\) algebra implemented.

The Frozen Input

The CAS-ready specification for the window-size calculation is:

\(U = U_0 e^\xi, \qquad A_0^{\rm bg} = eA_1(r), \qquad A_i^{\rm bg} = 0,\)

\(L_\mu = l_\mu + D_\mu\xi + \tfrac12[\xi,D_\mu\xi] + O(\xi^3),\)

\(R_\mu = U_0\left(l_\mu + \partial_\mu\xi + \tfrac12[\xi,\partial_\mu\xi]\right)U_0^\dagger + O(\xi^3),\)

together with one fixed explicit Goldstone–Wilczek current representative:

\(j_B^\mu = -\frac{1}{24\pi^2}\epsilon^{\mu\nu\alpha\beta}\left\{{\rm tr}(L_\nu L_\alpha L_\beta) – \frac{3ie}{2}\partial_\nu[A_\alpha{\rm tr}(\tau^3(L_\beta+R_\beta))]\right\}\)

and with the charge matrix fixed as \(Q = {\rm diag}(2/3, -1/3) = \tau_3/2 + \mathbf 1/6\).

Background Maurer–Cartan forms in the frozen local frame with \(n = e_3\):

\(l_1 = \sqrt{X_T}\,e_1, \qquad l_2 = \sqrt{X_T}\,e_2, \qquad l_3 = \sqrt{X_R}\,e_3,\)

\(X_T = \frac{\sin^2 f}{r^2}, \qquad X_R = f’^2.\)

One verified building block from a direct recomputation, useful as a cross-check for the CAS:

\(l_\theta|_{\rm pole} = i\left(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2\right),\)

with \(-\tfrac12{\rm Tr}(l_\theta^2) = \sin^2 f\).

The Three Stages

  1. Unreduced local Hessian. Compute \(H_{0,1,2}\) and \(P_{0,1,2}^{\rm explicit}\) on the fixed background, retaining \(A_1, A_1’\) and any necessary background jets. Keep \(U_2\) entirely out.
  2. Gauss reduction. Construct the physical \(K, S, P\) pencil from the unreduced system.
  3. Profile response. Add \(D_{U_2}H_0\) and \(D_{U_2}P_0\) only when solving the physical \(O(e^2)\) window problem.

The Definitions

\(P_{\rm unred}(e) = P_0 + eP_1 + e^2\left(P_{2,\rm explicit} + D_{U_2}P_0\right) + O(e^3)\)

\(H_{\rm unred}(e) = H_0 + eH_1 + e^2\left(H_{2,\rm explicit} + D_{U_2}H_0\right) + O(e^3)\)

followed by Gauss reduction of the pair \((H, P)\).

Correction to the six-class decomposition

The six classes (A, B, D, E, F, H) are useful schematically but should not be given to the CAS as an exhaustive list. The safest executable definition is

\(P_{2,\rm explicit}^{mm} = \tfrac12\left.\partial_e^2\frac{\delta^2\mathcal O_c}{\delta\xi\,\delta\xi}\right|_{e=0,\xi=0,a=0,U=U_0}\)

with the frozen input. The six classes are then cross-checks of the CAS expansion rather than assumptions about its completeness.

Correction to the verification limits

For a regular B = 1 hedgehog, \(f(r) = \pi + ar + O(r^3)\), so \(X_R \to a^2\) and \(X_T \to a^2\) at the center. The center is the isotropic limit \(X_R = X_T = a^2\), not \(X_R = 0\). The \(X_R = 0\) limit is an artificial local diagnostic.

Even at \(X_R = X_T\), radial and transverse entries of \(P_{2,\rm explicit}^{mm}\) need not be equal. The electromagnetic structure introduces the fixed generator \(Q_{\rm iso} = \tau_3/2\) and the Coulomb gradient \(\nabla A_1 = A_1′(r)\hat r\), which can break the degeneracy. The correct check is covariance under the residual symmetry of the full background including the EM spurions.

The fixed-background calculation should not include Gauss-reduced \(a_0\).

For the unreduced fixed-background \(mm\) Hessian, \(a_\mu = 0\) means the photon fluctuation is zero, while \(A_0^{\rm bg} = eA_1\) remains. Compute \(P_{\rm unred}\) first. Gauss reduction comes afterward and uses the constraint derived from the ordinary quadratic action \(H\). Otherwise the explicit \(P_2^{mm}\) and the induced pullback through the Gauss constraint get mixed together.

Part XII — The Computational Boundary

Why the Calculation Stops Here

The explicit \(P_{2,\rm explicit}^{mm}\) matrix requires evaluating

\(\left.\frac{\delta^2}{\delta\xi^a\delta\xi^b}\left[J_B^\mu J_B^\nu\,{\rm Tr}(\nabla_\mu L_\alpha\nabla_\nu L^\alpha)\right]\right|_{\xi=a=0}\)

at \(O(e^2)\), with the fixed GW current and the frozen \(L, R\) expansion. This requires:

  • explicit \(\mathfrak{su}(2)\) index contraction of the background \(l_i^a\) with the fluctuation \(\xi^a\),
  • expansion of \(L_\mu + R_\mu\) in the local frame with \(k \parallel e_3\),
  • the \(e^2\) GW current evaluated on the Coulomb background \(A_1(r)\), including \(A_1′(r)\),
  • the derivative structure \(D_\mu\xi\), \(\partial_\mu\xi\), and their commutators.

Doing this by hand in text would produce errors that cannot be detected — sign errors in commutators, misplaced \(U_0\) conjugations, index mismatches, confusion between \(A_1\), \(A_1’\), and the constrained \(a_0\). Any one would propagate into the matrix and produce a wrong result that looks plausible.

Clean computational boundary

The frozen input is unambiguous. The calculation is finite and local. The next nontrivial result — the explicit matrix \(P_{2,\rm explicit}^{mm}\) — requires a CAS with the \(\mathfrak{su}(2)\) algebra implemented. What has stopped here is the attempt to calculate the size of the neighborhood, not the existence result.

What Can Be Checked Once the Matrix Exists

  1. Hermiticity. The matrix should be Hermitian.
  2. Reduction at \(e=0\). It should reduce to \(P_0^{mm}\).
  3. Static limit. The \(\xi = 0\) limit should reproduce the static background.
  4. Residual symmetry. The matrix should transform covariantly under the residual symmetry of the full background including EM spurions, not simply radial = transverse.
  5. Invariant cross-check. The pole value \(l_\theta|_{\rm pole} = i(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2)\) and the invariant \(-\tfrac12{\rm Tr}(l_\theta^2) = \sin^2 f\) should be reproduced by the background algebra used in the CAS input.
  6. Chirality cross-check. The Cartesian combination \(l_x – i l_y = \tfrac{i\sin f}{r}e^{if}\tau_-\) should be reproduced by the CAS background.
  7. Dominant term. Identify whether the Schur term or the direct \(N_2\) term is larger, and what the resulting scaling of \(\epsilon\) is.

Part XIII — Corrections Along the Way

Correction 1 — The four-form vanishes for SU(2)

The candidate \(W = \varepsilon^{\mu\nu\rho\sigma}{\rm Tr}(L_\mu L_\nu L_\rho L_\sigma)\) vanishes identically because four Maurer–Cartan one-forms live in a three-dimensional Lie algebra.

Correction 2 — The kernel identity

The candidate \(\mathcal O = {\rm Tr}(B^\mu B^\nu\partial_\mu L_\nu)\) is identically zero because \({\rm Tr}(L_\nu)=0\).

Correction 3 — The mixed Hessian error

The implication \(\delta_B X_{00}=0 \Rightarrow \delta_\Omega\delta_B X_{00}=0\) was invalid. The correct chain uses \(\delta_B Y_{0\alpha}=0\), which follows from the staticity of the magnetic tangent.

Correction 4 — The rotational tangent

The claim \(\delta_\Omega\nabla_0 L_i = 0\) was wrong. The collective rotational zero mode is not a time-independent isorotation; \(\delta_\Omega\nabla_0 L_i = [\omega, l_i]\) is one of the objects responsible for the neutral rotor matrix element.

Correction 5 — The \(p_0^4\) piece

The quadratic principal symbol of \(\mathcal O_c\) is not only \(p_0^2|p|^2\). The \(\alpha=0\) term contributes a \(p_0^4\) piece, invisible in the rigid-rotor calculation but essential for the principal-symbol test. For the plane wave, \(\partial_0\partial_0\xi = -\omega^2\xi\) and \(\partial_0\partial_3\xi = \omega k\,\xi\), giving the Minkowski sum \(\omega^4 – \omega^2 k^2 = \omega^2(\omega^2 – k^2)\).

Correction 6 — The Skyrme term is not a complication

The sigma model alone is luminal: \(P_{c,\rm prin} \propto (\omega^2 – k^2)\), characteristic \(\omega^2 = k^2\), both vanish simultaneously. The Skyrme term is what splits the transverse cone away from Minkowski while \(P_{c,\rm prin}\) retains the Minkowski factor. The obstruction comes from the Skyrme term.

Correction 7 — The hedgehog center

For the standard B = 1 hedgehog, \(f(r) = \pi + ar + O(r^3)\), so \(f'(0) = a\) can be nonzero. The obstruction need not disappear at the center. What becomes isotropic there is \(X_R = X_T\), not \(X_R = 0\).

Correction 8 — The Gauss constraint

The earlier gauge-fixing argument using temporal gauge plus \(\partial_i A_i = 0\) was too quick. The correct reduction is Coulomb gauge plus solving Gauss’s law for \(A_0\). The physical kinetic block has the Skyrme-modified coefficients \(K_T = A + C(X_T+X_R)\) and \(K_R = A + 2CX_T\), both positive.

Correction 9 — The size of the small-coupling window

An earlier version suggested the physical coupling was probably inside the window based on an order-one prefactor estimate. That estimate was not supported. The existence theorem gives \(\epsilon > 0\); it does not give a naturalness bound on \(\epsilon\). No quantitative lower bound on \(\epsilon\) has been derived.

Correction 10 — The O(e) block structure

The statement \(P_1 = 0\) was too strong. The correct statement is \(P_1^{mm} = 0\), i.e., the matter–matter block vanishes. The \(O(e)\) correction is matter–photon off-diagonal. This is sufficient because it implies \(\Pi_T P_1 \Pi_T = 0\) and closes the radial-matter loophole.

Correction 11 — The radial–photon degeneracy

The radial–photon degeneracy at \(\lambda_R = \lambda_\gamma = k^2\) is not a singularity in the Schur complement for the transverse cluster. The resolvent is evaluated at \(\lambda_T\), and both radial and photon states have denominator \(k^2 – \lambda_T = \Delta > 0\).

Correction 12 — The \((ea[Q,\xi])^2\) term

The term \((ea[Q,\xi])^2\) is quartic in fluctuations, not a quadratic Hessian term. Direct \(N_2^{mm}\) terms come from \(O(e^2)\) background Coulomb/profile corrections and from the Gauss-reduced quadratic action.

Correction 13 — The Gauss source

The statement \(\rho_{\rm matter} = e\,{\rm Tr}(Q[l_0,\xi])\) and the conclusion \(a_0 = O(e^2)\xi\) were both wrong. The linearized charge density generally contains time-derivative terms \(J^0_{\rm lin} \sim e\,\mathcal Q(U_0)\dot\xi\), even though \(l_0 = 0\). At Fourier frequency \(\omega\), \(a_0 \sim e\omega\mathcal Q\xi/k^2 + O(e^2)\). So \(a_0 = O(e)\xi\), and eliminating it still produces an \(O(e^2)\) matter–matter contribution.

Correction 14 — The \(K, S\) expansion

The full physical matrices are \(K = K_0 + eK_1 + e^2K_2 + \cdots\) and \(S = S_0 + eS_1 + e^2S_2 + \cdots\). Only the matter–matter diagonal blocks have no \(O(e)\) term.

Correction 15 — Normalization

If \(K(e) = K_0 + eK_1 + e^2K_2 + \cdots\), then \(K_1\) is the coefficient of \(e\) and contains no additional \(e\). With \(D_\mu U = \partial_\mu U – ie a_\mu[Q,U]\), the \(O(e)\) block is \((K_1^{m\gamma})_{ai} = \kappa_{ai}\), not \(e\kappa_{ai}\).

Correction 16 — The \(P_2\) sources

One photon insertion from minimal coupling carries one explicit power of \(e\), not two. At quadratic fluctuation order, the \(e^2\) Hessian contributions must be classified by both coupling order and fluctuation degree. Terms such as \(e^2a^2\xi^2\) are fourth order in fluctuations and irrelevant to \(P^{(2)}\).

Correction 17 — The projector pullback

The “first-order projector correction” and “first-order eigenvector correction” are two representations of the same first-order movement of the subspace. Both vanish at \(O(e)\) under the block structure. At \(O(e^2)\), the pullback contains several pieces: \(P_{\rm eff}^{(2)} = V_0^\dagger P_2 V_0 + V_1^\dagger P_1 V_0 + V_0^\dagger P_1 V_1 + V_1^\dagger P_0 V_1 + V_2^\dagger P_0 V_0 + V_0^\dagger P_0 V_2\).

Correction 18 — The anomaly-divergence prescription

The baryon current should not be defined by the anomaly-divergence prescription. For vector baryon number in the two-flavor electromagnetic theory, \(U(1)_B\) is non-anomalous with respect to electromagnetism. The correct definition is by source variation: \(J_B^\mu = \delta S_{\rm fixed}[U,A,\mathcal B]/\delta\mathcal B_\mu|_{\mathcal B=0}\).

Correction 19 — The charge matrix

The identity piece of \(Q\) drops from the commutator \([Q,U]\) in \(D_\mu U\), but does not drop from traces such as \({\rm Tr}(Q^2)\) or from source/WZ couplings. The standard two-flavor choice is \(Q = {\rm diag}(2/3, -1/3) = \tau_3/2 + \mathbf 1/6\).

Correction 20 — The \(L_\mu, R_\mu\) expansion

The proposed expansion of \(L_\beta + R_\beta\) at \(O(\xi^2)\) was wrong. The conjugating \(U = U_0 e^\xi\) itself fluctuates, so one cannot obtain \(R_\beta^{(2)}\) simply by conjugating \(L_\beta^{(2)}\) with \(U_0\). The correct expansion is given in the frozen input above.

Correction 21 — The topological current through \(U_2\)

The statement “the topological current has no explicit \(e\), so it does not contribute to \(P_2^{mm}\)” is false once evaluated on the \(e\)-dependent background. It does contribute indirectly through \(U_2\), and that contribution belongs to the background-response sector \(P_{2,\rm bg}^{mm}\).

Correction 22 — The Bardeen contribution

Even if the Bardeen contribution to \(J_B^\mu\) is \(U\)-independent, the product \(J_B^\mu J_B^\nu X_{\mu\nu}\) acquires a matter Hessian from the \(U\)-independent \(J_B\) multiplying the \(\xi\)-dependence of \(X_{\mu\nu}\). So “its \(\xi\)-variation is zero” is not sufficient to conclude “it contributes nothing to \(P_2^{mm}\).”

Correction 23 — Pole value of \(l_\theta\): attribution and value

The direct calculation of the transverse Maurer–Cartan form at the pole, under the convention \(U_0 = \cos f + i(\tau\cdot n)\sin f\), gives

\(l_\theta|_{\rm pole} = i\left(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2\right).\)

The transcript text as received reports the pole value as \(i(\tfrac12\sin^2 f\,\tau_1 + \sin^2 f\,\tau_2)\). The two forms differ in the \(\tau_1\) coefficient: \(\sin f\cos f = \tfrac12\sin 2f\) versus \(\tfrac12\sin^2 f\). These are different functions of \(f\); no generator normalization reconciles them.

The invariant \(-\tfrac12{\rm Tr}(l_\theta^2) = \sin^2 f\) holds for the direct-calculation form. For the transcript-text form, \(-\tfrac12{\rm Tr}(l_\theta^2) = \tfrac54\sin^4 f\), which fails the invariant except when \(\sin^2 f = 4/5\). The invariant cleanly distinguishes the two.

The most plausible explanation is a \(\sin 2f \to \sin^2 f\) transcription slip inside the transcript text, not an error in the underlying session. The direct-calculation value is the correct one and is Reproducible-here. The exact form of the transcript’s quoted string is a property of the transcript, not of the mathematics.

Correction 24 — Two-part status of the small-e theorem

The small-e charged theorem has two logically distinct parts. The e = 0 cohomological anchor — Parts IV–VII, comprising Gate 1, the source-derived current check, the principal-symbol obstruction, and the divergence-loophole removal — is Reproducible-here. The continuation portion — existence and smoothness of the coupled rotating branch in e, Fredholm invertibility of the linearized operator on weighted spaces after zero-mode projection, and the smoothness of the Riesz projector — is Asserted-not-inspectable. The joint theorem inherits the weaker label.

Correction 25 — Earlier \(l_y\) error and the phase-lock derivation

An earlier hand attempt at the circular combination \(l_x – i l_y\) used

\(l_y = \tfrac1r(-s^2\tau_1 + i s c\,\tau_2), \qquad s = \sin f,\ c = \cos f,\)

which is not anti-Hermitian: the \(-s^2\tau_1/r\) piece is Hermitian. The correct expression, from \(l_y = U_0^\dagger\partial_y U_0\) at the pole with \(\partial_y n = e_2/r\), is

\(l_y = \tfrac{i}{r}(-s^2\tau_1 + s c\,\tau_2).\)

With the corrected pair, \(l_x – i l_y = \tfrac{s}{r} e^{if}(i\tau_1 + \tau_2) = \tfrac{i\sin f}{r} e^{if}\tau_-\). The single-chirality structure and the \(e^{if}\) phase are therefore Reproducible-here. The exact transcript string \(2\sin f\,e^{if}\) and any claim about its derivation remain Asserted-not-inspectable.

Part XIV — Addendum: Pole Phase-Lock Structure

Purpose

This addendum records a background-algebra result that has been independently reconstructed in this record: the single-chirality, \(e^{if}\)-phase structure of the transverse Maurer–Cartan combination at the pole. It also clarifies the attribution of Correction 23 and flags an open structural subtlety about the transverse fluctuation at the pole.

Section 1 — Clarification on Correction 23

Correction 23’s substantive claim is correct with respect to the transcript text as received: the transcript’s quoted pole value of \(l_\theta\) differs from the direct calculation. Correction 23 already gives the direct-calculation value \(i(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2)\), which is the correct form. It attributes the \(\tfrac12\sin^2 f\) form to the transcript. If the underlying session produced \(\sin f\cos f\), then the discrepancy is inside the transcript’s transcription, and the correct action is to reword Correction 23’s attribution rather than overturn it. The invariant check confirms the direct-calculation form and the failure of the \(\tfrac12\sin^2 f\) form.

Section 2 — Direct value of \(l_\theta\)

Under \(U_0 = \cos f + i(\tau\cdot n)\sin f\), at the north pole \(\theta = 0\), \(\varphi = 0\):

\(l_\theta|_{\rm pole} = i(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2).\)

The \(\tau_1\) coefficient is \(\sin f\cos f = \tfrac12\sin 2f\). It is independent of the left- or right-acting Maurer–Cartan convention.

Derived Reproducible-here

Section 3 — Invariant check

The invariant \(-\tfrac12{\rm Tr}(l_\theta^2) = \sin^2 f\) holds for the form above in the Pauli convention \(\mathrm{Tr}(\tau_a\tau_b) = 2\delta_{ab}\):

\(l_\theta^2 = -\sin^2 f\cos^2 f\,\mathbf 1 – \sin^4 f\,\mathbf 1 = -\sin^2 f\,\mathbf 1.\)

The alternative \(\tfrac12\sin^2 f\) form gives \(l_\theta^2 = -\tfrac14\sin^4 f\,\mathbf 1 – \sin^4 f\,\mathbf 1 = -\tfrac54\sin^4 f\,\mathbf 1\), hence \(-\tfrac12{\rm Tr}(l_\theta^2) = \tfrac54\sin^4 f\), which fails the invariant except when \(\sin^2 f = 4/5\). The invariant cleanly distinguishes the two forms and confirms the Section 2 value.

Derived Reproducible-here

Section 4 — Circular combination and phase-lock

Direct Cartesian calculation at the pole, with \(\partial_x n = e_1/r\), \(\partial_y n = e_2/r\), gives

\(l_x = \tfrac{i}{r}(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2),\)

\(l_y = \tfrac{i}{r}(-\sin^2 f\,\tau_1 + \sin f\cos f\,\tau_2).\)

Consequently,

\(l_x – i l_y = \tfrac{i\sin f}{r} e^{if}\tau_- = \tfrac{2i\sin f}{r} e^{if} T_-,\)

with \(T_- = \tau_-/2\).

The single-chirality structure and the \(e^{if}\) phase are reproducible here. The factor \(2\) appears only when using \(T_-\). The overall \(i/r\) factor is not part of the transcript’s bare coefficient; whether the transcript’s exact statement \(2\sin f\,e^{if}\) referred to the coefficient after stripping the conventional \(i/r\) factor cannot be determined without the underlying calculation.

Derived Reproducible-here for the \(e^{if}\tau_-\) structure. The exact transcript string remains Asserted-not-inspectable.

Section 5 — Open item: the transverse fluctuation at the pole

A transverse fluctuation of the soliton at the pole is like a p-orbital vanishing at its origin: its value vanishes, its angular derivative does not. The well-defined object at the pole is the derivative of the transverse components in the \(x, y\) directions, not their value. This was identified during the session and flagged, not resolved. Any phase-locked ansatz for the transverse fluctuation must be built with this distinction explicit from the start.

Open

Section 6 — What the addendum does not establish

  • The “twice the rate” precession claim. The \(e^{if}\) phase in the Maurer–Cartan form implies a covariant derivative with phase rate \(f’\), not \(2f’\), unless the comparison is to a different quantity. The claim requires its own derivation.
  • The exact transcript string \(2\sin f\,e^{if}\). The mathematical form \(l_x – i l_y = \tfrac{i\sin f}{r} e^{if}\tau_-\) is reproducible here. Whether the transcript stripped the \(i/r\) factor and how it named the coefficient cannot be determined.
  • The remaining transcript-reported items — \(l_\varphi\), \(\nabla_\mu l_\alpha\), any \(e^2\) coefficient — remain asserted-not-inspectable.

Closing State

The derivation produced the following frozen status.

ClaimLogical statusEvidentiary basis
Neutral topological-current non-protection lemmaProvedReproducible-here
Gate 1: mixed Hessian vanishesProvedReproducible-here
Source-derived current checkProvedReproducible-here
Principal-symbol cohomological obstructionDerivedReproducible-here
Divergence loophole removed by Euler operatorDerivedReproducible-here
\(O(e)\) block identities \(K_1^{mm} = S_1^{mm} = P_1^{mm} = 0\)DerivedReproducible-here
Pole value \(l_\theta|_{\rm pole} = i(\sin f\cos f\,\tau_1 + \sin^2 f\,\tau_2)\)DerivedReproducible-here
Invariant \(-\tfrac12{\rm Tr}(l_\theta^2) = \sin^2 f\)DerivedReproducible-here
Pole phase-lock structure \(l_x – i l_y = \tfrac{i\sin f}{r} e^{if}\tau_-\)DerivedReproducible-here
Small-e charged Skyrme non-protection theoremConditionalAnchor reproducible-here; continuation asserted-not-inspectable
Finite-k subprincipal transverse operator \(P_{\rm sub}^{(T)}\)OpenOpen
Circular-polarization cancellation within \(P_{\rm sub}^{(T)}\)OpenOpen
\(P_{2,\rm explicit}^{mm}\)Not calculatedCAS required
\(D_{U_2}P_0^{mm}\)OpenRequires \(f_2(r)\)
Numerical small-e windowUndeterminedCAS required
All-e continuationOpenOpen
The general response identityOpenOpen
Exceptional structures (SUSY, hidden symmetry, geometric locking)OpenOpen
Transcript string \(2\sin f\,e^{if}\) and any claim about its exact normalization—Asserted-not-inspectable
“Twice the rate” precession claim—Asserted-not-inspectable
Transcript-reported \(l_\varphi\), \(\nabla_\mu l_\alpha\), any \(e^2\) coefficient—Asserted-not-inspectable; excluded
Labels are sticky and per-result. A claim moves category only when the underlying derivation is recovered or the calculation is independently reproduced. Reconstructing \(l_\theta|_{\rm pole}\) and the phase-lock structure upgrades those two results and does not upgrade the neighbouring transcript-reported items. The remaining asserted-not-inspectable claims are not premises for further derivation.
The e = 0 anchor and the continuation. The principal-symbol cohomological obstruction — the highest-order-homogeneous-degree failure of the Euler-operator identity — is reproducible from the present record. The small-e theorem additionally requires the coupled-branch continuation and Riesz-projector smoothness, which are not displayed here and remain asserted-not-inspectable.

What Remains Open

  1. The coupled-branch continuation. Weighted-space setup, Fredholm invertibility, and Riesz-projector smoothness. Not displayed. The small-e theorem is conditional on them.
  2. The finite-k subprincipal transverse operator \(P_{\rm sub}^{(T)}\). Whether, after summing every contribution at the relevant symbol order, \(P_{\rm sub}^{(T)} = p_T I_2\) or contains a surviving \(p_A J_3\) with \(p_A \neq 0\). This is a question about the full local quadratic operator beyond its principal symbol; it does not affect the principal-symbol obstruction.
  3. The circular-polarization cancellation. Follows from the above.
  4. \(P_{2,\rm explicit}^{mm}\) and \(D_{U_2}P_0^{mm}\). Requires a CAS, with the frozen input above.
  5. The numerical size of the window. Requires the above.
  6. The transverse fluctuation at the pole. A transverse fluctuation vanishes at the pole like a p-orbital at its origin; the well-defined object is its derivative in the \(x, y\) directions, not its value. The phase-locked ansatz must be rebuilt with this distinction explicit.
  7. The “twice the rate” precession claim. The \(e^{if}\) phase implies a covariant derivative with phase rate \(f’\), not \(2f’\), unless the comparison is to a different quantity. Requires its own derivation.
  8. All-e continuation. The result holds for sufficiently small nonzero e, not for all e up to the physical coupling.
  9. The general response identity. The classification of local identities capable of enforcing \(\mathscr R_\Theta = (q/M)\mathscr R_g\) modulo EOM, total derivatives, and gauge identities is open.
  10. Exceptional structures. Whether any purely bosonic structure — supersymmetry, hidden symmetry, constrained operator algebra, geometric locking — can enforce current–metric locking is untouched.

The Honest Summary

The derivation produced a proved neutral lemma, a reproducible principal-symbol cohomological obstruction for the charged case, and a small-e charged theorem whose e = 0 anchor is reproducible but whose continuation portion is not. The pole value of the transverse Maurer–Cartan form has been independently verified, as has the invariant \(-\tfrac12{\rm Tr}(l_\theta^2) = \sin^2 f\) and the pole phase-lock structure \(l_x – i l_y = \tfrac{i\sin f}{r} e^{if}\tau_-\). The numerical window and the exceptional-structure question remain open. The remaining transcript-reported items are excluded pending inspectable output.

The problem is no longer “find a clever soliton profile that gives g = 2.” It is: does there exist a microscopic identity whose local response content forces the electromagnetic magnetic-response functional and the rotational kinetic functional to be the same functional up to q/M?

Record of a derivation. Proved results labeled as proved. Conditional results labeled as conditional. Corrections recorded alongside the claims they correct. The evidentiary categories — reproducible-here, reproducible from available source, asserted-not-inspectable, open — are sticky and per-result. The neutral lemma, the principal-symbol cohomological obstruction, the pole value of \(l_\theta\), the invariant \(-\tfrac12{\rm Tr}(l_\theta^2) = \sin^2 f\), and the pole phase-lock structure \(l_x – i l_y = \tfrac{i\sin f}{r} e^{if}\tau_-\) are reproducible from the present record. The small-e charged theorem is conditional on asserted-not-inspectable continuation assumptions. The numerical window is undetermined and has reached a clean computational boundary requiring a CAS. The remaining transcript-reported background algebra is excluded pending inspectable output. All-e continuation, the general response identity, and exceptional locking mechanisms are listed as open problems, not unfinished steps.